My Math Forum Binomial distribution and Poisson help please £20 gift card for amazon

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 November 10th, 2016, 12:03 PM #2 Senior Member     Joined: Sep 2015 From: USA Posts: 2,430 Thanks: 1315 7) is a binomial distribution since the cartons are returned $p=0.2,~N=4$ a) none were undamaged means all 4 were damaged. The probability of this is $(0.2)^4 = 0.0016$ b) at least 3 were undamaged so at max 1 was damaged. This is the probability that either 0 or 1 was damaged which is $(0.8 )^4 + \begin{pmatrix}4 \\ 1\end{pmatrix} (0.2)(0.8 )^3 = 0.8192$

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