My Math Forum A continuous probability distributions problem

 Probability and Statistics Basic Probability and Statistics Math Forum

 October 16th, 2016, 11:55 PM #1 Newbie   Joined: Oct 2016 From: United States Posts: 1 Thanks: 0 Suppose we observe 84 alcoholics with cirrhosis of the liver, of whom 29 have hepatomas - that is liver-cell carcinoma. Suppose we know, based on large sample, that the risk of hepatoma among alcoholics without cirrhosis of the liver is 24%. 5.50 what is the probability that we observe exactly 29 alcoholics with cirrhosis of the liver who have hepatomas if the true rate of hepatoma among alcoholics (with or without cirrhosis of the liver) is .24? 5.51 What is the probability of observing at least 29 hepatomas among the 84 alcoholics with cirrhosis of the liver under the assumptions in problem 5.50? Last edited by skipjack; October 17th, 2016 at 05:34 AM.
 October 17th, 2016, 11:10 AM #2 Global Moderator   Joined: May 2007 Posts: 6,629 Thanks: 622 Both questions can be answered exactly using the binomial distribution. The probability of exactly k concurrences of an event in a sample of size n is given by $\displaystyle \binom {n}{k}p^k(1-p)^{n-k}$ where p is the probability of one occurrence. For your problems, n=84 and p=0.24. For 5.50 the probability is given for k=29. For 5.51 the probability is $\displaystyle \sum_{k=29}^{84}\binom {n}{k}p^k(1-p)^{n-k}$. Thanks from caty

 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post cmkluza Probability and Statistics 1 April 4th, 2015 06:00 AM Chee Probability and Statistics 1 June 1st, 2012 12:48 AM koricha25 Advanced Statistics 0 May 19th, 2012 01:05 PM Natalie89 Advanced Statistics 1 February 13th, 2011 05:44 PM

 Contact - Home - Forums - Cryptocurrency Forum - Top