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October 3rd, 2016, 01:12 PM   #1
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Bionomial Probability

46%​ of men consider themselves professional baseball fans. You randomly select 10 men and ask each if he considers himself a professional baseball fan. Find the probability that the number who consider themselves baseball fans is​ (a) exactly​ five, (b) at least​ six, and​ (c) less than four


(A). P(5) = 10C5 (0.46)^5(0.54)^5
= 252(0.46)^5(0.54)^5
= 0.238
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October 3rd, 2016, 02:02 PM   #2
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Exactly k, $\displaystyle P_k=\binom{10}{k}.46^k\times .54^{10-k}$

For b, $\displaystyle \sum_{k=6}^{10}P_k$
For c, $\displaystyle \sum_{k=0}^{3}P_k$
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October 3rd, 2016, 02:13 PM   #3
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How do I go about putting it into the calculator for (B) and (C)?

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Originally Posted by mathman View Post
Exactly k, $\displaystyle P_k=\binom{10}{k}.46^k\times .54^{10-k}$

For b, $\displaystyle \sum_{k=6}^{10}P_k$
For c, $\displaystyle \sum_{k=0}^{3}P_k$
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October 4th, 2016, 01:43 PM   #4
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Originally Posted by rihnavy View Post
How do I go about putting it into the calculator for (B) and (C)?
Calculate P for each k that you need and add them up as described.
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