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October 3rd, 2016, 02:12 PM  #1 
Newbie Joined: Oct 2016 From: United States Posts: 5 Thanks: 0  Bionomial Probability
46% of men consider themselves professional baseball fans. You randomly select 10 men and ask each if he considers himself a professional baseball fan. Find the probability that the number who consider themselves baseball fans is (a) exactly five, (b) at least six, and (c) less than four (A). P(5) = 10C5 (0.46)^5(0.54)^5 = 252(0.46)^5(0.54)^5 = 0.238 
October 3rd, 2016, 03:02 PM  #2 
Global Moderator Joined: May 2007 Posts: 6,438 Thanks: 562 
Exactly k, $\displaystyle P_k=\binom{10}{k}.46^k\times .54^{10k}$ For b, $\displaystyle \sum_{k=6}^{10}P_k$ For c, $\displaystyle \sum_{k=0}^{3}P_k$ 
October 3rd, 2016, 03:13 PM  #3 
Newbie Joined: Oct 2016 From: United States Posts: 5 Thanks: 0  
October 4th, 2016, 02:43 PM  #4 
Global Moderator Joined: May 2007 Posts: 6,438 Thanks: 562  

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