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 October 3rd, 2016, 02:12 PM #1 Newbie   Joined: Oct 2016 From: United States Posts: 5 Thanks: 0 Bionomial Probability 46%​ of men consider themselves professional baseball fans. You randomly select 10 men and ask each if he considers himself a professional baseball fan. Find the probability that the number who consider themselves baseball fans is​ (a) exactly​ five, (b) at least​ six, and​ (c) less than four (A). P(5) = 10C5 (0.46)^5(0.54)^5 = 252(0.46)^5(0.54)^5 = 0.238
 October 3rd, 2016, 03:02 PM #2 Global Moderator   Joined: May 2007 Posts: 6,663 Thanks: 649 Exactly k, $\displaystyle P_k=\binom{10}{k}.46^k\times .54^{10-k}$ For b, $\displaystyle \sum_{k=6}^{10}P_k$ For c, $\displaystyle \sum_{k=0}^{3}P_k$
October 3rd, 2016, 03:13 PM   #3
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How do I go about putting it into the calculator for (B) and (C)?

Quote:
 Originally Posted by mathman Exactly k, $\displaystyle P_k=\binom{10}{k}.46^k\times .54^{10-k}$ For b, $\displaystyle \sum_{k=6}^{10}P_k$ For c, $\displaystyle \sum_{k=0}^{3}P_k$

October 4th, 2016, 02:43 PM   #4
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Quote:
 Originally Posted by rihnavy How do I go about putting it into the calculator for (B) and (C)?
Calculate P for each k that you need and add them up as described.

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### 51​%of men consider themselves professional baseball fans. you randomly select 10 men and ask each if he considers himself a professional baseball fan. find the probability that the number who consider themselves baseball fans is​ (a) exactly​ five,

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