My Math Forum An art gallery has a total of 11 paintings by a particular artist

 Probability and Statistics Basic Probability and Statistics Math Forum

 April 21st, 2016, 03:46 AM #1 Newbie   Joined: Apr 2016 From: DUBAI Posts: 2 Thanks: 0 An art gallery has a total of 11 paintings by a particular artist An art gallery has a total of 11 paintings by a particular artist; of these, 5 are oil paintings and 6 are water colour paintings. The art gallery is asked to provide a special exhibition of this artistâ€™s work but is restricted to showing only five of the paintings. Calculate the number ways in which the five paintings can be selected for the exhibition if : there are no restrictions one particular painting must be included there must be exactly three watercolour paintings there must be more watercolour paintings than oil paintings
 April 21st, 2016, 04:25 AM #2 Senior Member   Joined: Dec 2012 From: Hong Kong Posts: 853 Thanks: 311 Math Focus: Stochastic processes, statistical inference, data mining, computational linguistics 1. I'm sure you can do this one yourself. 2. Choose four paintings out of the remaining 10. 3. Then there must be exactly two oil paintings. Choose two oil paintings out of five, then three water paintings out of 6. 4. Then any of these cases is possible: 5 watercolour, no oil 4 watercolour, 1 oil 3 watercolour, 2 oil For each of these cases, calculate how many combinations are possible, then sum everything up.
 April 22nd, 2016, 08:18 AM #3 Math Team   Joined: Jan 2015 From: Alabama Posts: 3,264 Thanks: 902 1) You can choose any one of the 11 paintings first, then any one of the remaining 10 second, then any one of the remaining 9, then any one of the remaining 8, then any one of the remaining 7. That makes a total of 11*10*9*8*7 which can also be written as 11!/6!. 2) Take out the given painting first. That leaves 10 painting from which to choose the remaining 4 paintings. There are, as above, 10*9*8*7= 10!/6! ways to do that. 3) There are 6*5*4 ways to select the three watercolors from the 6. There are 5*4 ways to choose two of the 5 oil paintings. There are 6*5*4*5*4 ways to do this. 4) "More watercolors than oil" could be: 5 watercolors, no oil pantings: 6*5*4*3*2 4 watercolors, one oil: (6*5*4*3)(5) 3 watercolors, two oils: (6*5*4)(5*4) Add those.

 Tags art, artist, gallery, paintings, total

 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post sensational Probability and Statistics 1 June 10th, 2015 05:21 PM branny12000 Advanced Statistics 0 May 28th, 2013 04:37 AM J.Xavier New Users 8 April 18th, 2013 12:21 PM AamirAli Algebra 5 March 4th, 2013 01:39 AM Taurai Mabhena Differential Equations 11 January 30th, 2012 02:55 PM

 Contact - Home - Forums - Cryptocurrency Forum - Top