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February 26th, 2016, 12:00 PM   #1
Joined: Feb 2016
From: Illinois

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Mean and standard deviation of a discrete probability distribution

How would I get started solving this?

Air America has a policy of routinely overbooking flights because past experience shows that some passengers fail to show. In the probability distribution given below, the random variable x represents the number of passengers who cannot be boarded because there are passengers than seats. Find the mean and standard deviation of this probability distribution

x P(x)
0 0.809
1 0.123
2 0.057
3 0.009
4 0.002
Ore0Kidd is offline  
February 26th, 2016, 01:33 PM   #2
Joined: Apr 2014
From: Birmingham, AL

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mean= E[X] = sum(x*p(X=x))
variance = E[X^2]-E[X]^2 = sum(x^2*p(X=x))-(sum(x*p(X=x)))^2

Last edited by mathman; February 26th, 2016 at 05:14 PM.
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