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January 19th, 2016, 07:08 AM   #1
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combination permutation

Find the smallest values for m and n such that

A) mPn = 10C7

B) mCn = 15P2

My attempt:

A) 10C7 = 10!/(3!7!) = (10*9*8 )/(3*2) = 10*3*4 = 5*4*3*2 = 5P5

So m = n = 5

B) 15P2 = 15*14 = 3*5*7*2 = (7*6*5*4*3*2)/(4*6) = 7!/4! = 7P3
BUT I'm supposed to get mCn. I'm stuck. Please help. Thanks.
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