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January 19th, 2016, 07:08 AM  #1 
Senior Member Joined: Oct 2013 From: Far far away Posts: 431 Thanks: 18  combination permutation
Find the smallest values for m and n such that A) mPn = 10C7 B) mCn = 15P2 My attempt: A) 10C7 = 10!/(3!7!) = (10*9*8 )/(3*2) = 10*3*4 = 5*4*3*2 = 5P5 So m = n = 5 B) 15P2 = 15*14 = 3*5*7*2 = (7*6*5*4*3*2)/(4*6) = 7!/4! = 7P3 BUT I'm supposed to get mCn. I'm stuck. Please help. Thanks. 

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