My Math Forum combination permutation

 Probability and Statistics Basic Probability and Statistics Math Forum

 January 19th, 2016, 07:08 AM #1 Senior Member     Joined: Oct 2013 From: Far far away Posts: 429 Thanks: 18 combination permutation Find the smallest values for m and n such that A) mPn = 10C7 B) mCn = 15P2 My attempt: A) 10C7 = 10!/(3!7!) = (10*9*8 )/(3*2) = 10*3*4 = 5*4*3*2 = 5P5 So m = n = 5 B) 15P2 = 15*14 = 3*5*7*2 = (7*6*5*4*3*2)/(4*6) = 7!/4! = 7P3 BUT I'm supposed to get mCn. I'm stuck. Please help. Thanks.

mpn=10c7 permutation combination

Click on a term to search for related topics.
 Thread Tools Display Modes Linear Mode

 Similar Threads Thread Thread Starter Forum Replies Last Post mac07 Elementary Math 2 December 13th, 2014 12:22 AM talo0000 Algebra 4 June 8th, 2012 02:32 PM talo0000 Algebra 2 June 7th, 2012 01:32 PM bobomindfreak Advanced Statistics 0 February 23rd, 2012 12:43 PM KDroid Algebra 0 January 4th, 2012 10:21 PM

 Contact - Home - Forums - Cryptocurrency Forum - Top