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June 26th, 2012, 02:28 AM  #1 
Member Joined: Jan 2012 Posts: 52 Thanks: 0  Tricky Probability Problem
Hello, This seems to me a tricky probability problem, given that the answer I found is too easy to be correct. Can someone check, please? There are two cards: one of them has both sides in red and the other one has one side in red and the other side in blue. One of the cards is randomly picked and put over a table. If the side of the card showing up is red, give the probability of the other side being red also. My answer is: 1/2. Thanks! 
June 26th, 2012, 05:21 AM  #2 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 14,597 Thanks: 1038  Re: Tricky Probability Problem
2/3 same as 4 cards: b,r,r,r ; and you got one of the r's ': probability of picking a r from the remaining 3 
June 26th, 2012, 05:24 AM  #3  
Math Team Joined: Dec 2006 From: Lexington, MA Posts: 3,267 Thanks: 408  Re: Tricky Probability Problem Hello, tiba! You are halfright . . . It is a trick question. Quote:
Let's label the faces of the cards. [color=beige]. . [/color]Card1 has and [color=beige]. . [/color]Card2 has and You choose a card and place it on the table. You look at the top face of the card; it is red. There are THREE possible situations: [color=beige]. . [/color](1) You are looking at ; the other side is [color=beige]. . [/color](2) You are looking at ; the other side is [color=beige]. . [/color](3) You are looking at ; the other side is In TWO out of THREE cases, the other side is red. The probability is  
June 29th, 2012, 01:16 AM  #4 
Senior Member Joined: Jan 2010 Posts: 205 Thanks: 0  Re: Tricky Probability Problem
Never mind, I asked a really dumb question


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