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November 18th, 2015, 12:57 PM  #1 
Newbie Joined: Nov 2015 From: Boynton Beach, FL Posts: 5 Thanks: 0  Bounds of integration with inequality constraint
Hi, all. If the integral of a function when y>1 goes from 1 to infinity, then why does an integral of a function for 0<x<15 also start at 1 (and then of course go to 15)?

November 18th, 2015, 01:15 PM  #2 
Global Moderator Joined: May 2007 Posts: 6,807 Thanks: 717 
It doesn't sound right. Clarify! Actually the integral can be defined to be over a part of the domain.

November 18th, 2015, 01:46 PM  #3 
Math Team Joined: Dec 2013 From: Colombia Posts: 7,675 Thanks: 2655 Math Focus: Mainly analysis and algebra 
The most likely reason is that the function is zero between 0 and 1.

November 18th, 2015, 02:03 PM  #4 
Newbie Joined: Nov 2015 From: Boynton Beach, FL Posts: 5 Thanks: 0 
Sorry, but I don't understand either reply. Let me rephrase. The density function is f(y)=2/y^3 for y>1 and the integral goes from 1 to infinity. Another function is f(x) = 0.5003e^(x/2) for 0<x<15 and the integral goes from 1 to 15. Why is that? Sorry for taking so long to reply as I am new to this forum!

November 18th, 2015, 02:40 PM  #5 
Math Team Joined: Dec 2013 From: Colombia Posts: 7,675 Thanks: 2655 Math Focus: Mainly analysis and algebra 
Typo?

November 18th, 2015, 02:48 PM  #6 
Newbie Joined: Nov 2015 From: Boynton Beach, FL Posts: 5 Thanks: 0 
No, there is no typo.

November 19th, 2015, 01:51 PM  #7  
Global Moderator Joined: May 2007 Posts: 6,807 Thanks: 717  Quote:
 
November 19th, 2015, 02:00 PM  #8 
Newbie Joined: Nov 2015 From: Boynton Beach, FL Posts: 5 Thanks: 0 
Okay, please type "soa problems exam p" into the Google search engine and click on the first link. Then, look at problems 53 and 54 and explain why both integrand start at 1. Btw, there are also solutions if you type in the abovementioned quote and put solutions after what is already quoted. 
November 19th, 2015, 04:17 PM  #9 
Math Team Joined: Nov 2014 From: Australia Posts: 689 Thanks: 244 
They're probably accounting for the 1000 deductible. The first $1000 of damage don't matter.

November 20th, 2015, 03:33 AM  #10 
Newbie Joined: Nov 2015 From: Boynton Beach, FL Posts: 5 Thanks: 0 
I see! I knew I could count on you!


Tags 
bounds, constraint, inequality, integration 
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