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June 14th, 2011, 03:51 PM  #11 
Senior Member Joined: Apr 2007 Posts: 2,140 Thanks: 0 
greg1313, I got... P(c) = 2P(b) P(b) = 3P(a) P(a) + P(b) + P(c) = 1 P(a) + 3P(a) + 2*3P(a) = P(a) + 3P(a) + 6P(a) = 10P(a) = 1 ? P(a) = 1/10, P(b) = 3*1/10 = 3/10, P(c) = 2*3/10 = 3/5. Who's wrong? 
June 14th, 2011, 05:21 PM  #12  
Global Moderator Joined: Oct 2008 From: London, Ontario, Canada  The Forest City Posts: 7,968 Thanks: 1152 Math Focus: Elementary mathematics and beyond  Re: Probability Question!! Help! Quote:
Quote:
 
June 14th, 2011, 06:37 PM  #13 
Senior Member Joined: Apr 2007 Posts: 2,140 Thanks: 0 
You're welcome. Thanks for solving P(b) = 3P(a).

June 14th, 2011, 08:01 PM  #14  
Senior Member Joined: Apr 2011 From: USA Posts: 782 Thanks: 1  Re: Probability Question!! Help! Quote:
I figure if you're just doing a lot of equations, that's just a bunch of plug n chug and it means you can follow a process. I don't see that the same as understanding it, and understanding something means you can see it, or even feel it. I hate equations cause it's just abstract nonsense  I have to get a feel for what the equation means, usually trying to figure out how to do something without an equation first. Then I can deal with the equation  even though they're still abstract nonsense. I'm still seeing the "logic" of it, not a pretty picture at a museum. Do you think I could sell that picture for a lot of money if I called it Scarlet Concepts in Dancing Probabilities?  

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let s = {a, b, c} be a sample space for a particular experiment. furthermore, let e be the event that outcome a is observed, and f be the event that outcome c is not observed. if event e is 4 times as likely to not occur as it is to occur, and event f is,solve ques 11p in c pics
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