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May 28th, 2011, 09:47 PM   #11
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Re: confusing probability questions

I give up.
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May 29th, 2011, 10:42 PM   #12
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Re: confusing probability questions

Anyone can help to solve question 2 part (c) and (d)?
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May 31st, 2011, 06:01 AM   #13
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Re: confusing probability questions

Quote:
Originally Posted by hoyy1kolko
Anyone can help to solve question 2 part (c) and (d)?
Quote:
Originally Posted by rudrax
I don't know what is asked in 'd', first I assumed there was some typo...

For 'c' - Take three girls...let's make the problem little more interesting, so we will take three hot girls
A, B and C
Make groups of 2 girls, how many options 3C2=3=AB,BC,CA
Here we say AB=BA means order doesn't mater, but A as Opposer is not equals to A as Proposer
So in AB itself A has 2 options and B has 1(the remaining option)=2! options
AB(where A is Proposer, B is Opposer), BA(where B is Proposer, A is Opposer)

Then the correct count should be 3C2*2! or nCr*r! or 3P2
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June 4th, 2011, 04:22 PM   #14
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1. There are total of 6 balls = 5 black balls + 1 white ball.
Alan (1): Probability of winning = 1/6 and probability of not winning = 5/6
If Alan didn't win by the probability of 5/6, then 5 total = 4 black balls + 1 white ball.
Bill (2): Probability of winning = 1/5 and probability of not winning = 4/5
We repeat this process until there are two black balls and one white ball left. Assuming that Bill does not win by probability
of 2/3, now it's Alan's first turn for one black ball and one white ball remaining. If both Alan and Bill take turns and both of them not
winning by probability of 1/2 until the last turn of Bill, therefore winning by probability of 1/2.
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a class of 20 pupils consists of 12 girls and 8 boys.For a discussion session four officers are to be chosen at random as chairman, recorder,proposer, and oppeser..what is the probability that all four officers are girls is?
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6c5 probability

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probability that the proposer and opposer are both girls

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6classmathquestion

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new easy maths questions but confusing

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why is probability so confusing

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a class of 20 pupils consists of 12 girls and 8 boys.for a discussion session ,4 officers are to be chosen at random as chairman.proposer and opposer,find(a)the probability that all four officer are girls (b)the probability that 2 officers are girls and 2

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In statistics Aclass of twenty pupils consits of 12 girls and boys,for adiscussion session four officers are to be chosen at random as chairman,recorder,propose and opposer what is the probability that all four officers are girls

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confusing 6 class math question

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a class of 20 pupils consist of 12 girls and 8 boys.for a discussion session four officers are to be chosen at random as chairman,recorder,proposerand opposer.what is the probability that all officers are girls

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Aclass of 20 pupils consist of 12 girls and 8 boys for a discussionm session. 4 officers are to be chosen at random as chairman, recorder, proposer and opposer. The probability that all 4 officers are girls is

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how to come this answer 6C5 X 8C0 = 6X1= 6

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1.A box containing five black balls and one white ball.Alan and Bill take turns to draw a ball from box,starting with Alan.The first boy to draw the white ball wins the game. Assume that they do not replace the balls as they draw them out,find the probabi

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a class of 20 pupils , 12 girls , all officers are girls , probsbility

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7/20 of the pupils in a class are boys. The rest are girls. Find the percentage of girls in the class.

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