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May 28th, 2011, 09:47 PM  #11 
Member Joined: May 2011 Posts: 51 Thanks: 0  Re: confusing probability questions
I give up.

May 29th, 2011, 10:42 PM  #12 
Senior Member Joined: Dec 2010 Posts: 233 Thanks: 0  Re: confusing probability questions
Anyone can help to solve question 2 part (c) and (d)?

May 31st, 2011, 06:01 AM  #13  
Senior Member Joined: Sep 2010 Posts: 101 Thanks: 0  Re: confusing probability questions Quote:
Quote:
 
June 4th, 2011, 04:22 PM  #14 
Senior Member Joined: Apr 2007 Posts: 2,140 Thanks: 0 
1. There are total of 6 balls = 5 black balls + 1 white ball. Alan (1): Probability of winning = 1/6 and probability of not winning = 5/6 If Alan didn't win by the probability of 5/6, then 5 total = 4 black balls + 1 white ball. Bill (2): Probability of winning = 1/5 and probability of not winning = 4/5 We repeat this process until there are two black balls and one white ball left. Assuming that Bill does not win by probability of 2/3, now it's Alan's first turn for one black ball and one white ball remaining. If both Alan and Bill take turns and both of them not winning by probability of 1/2 until the last turn of Bill, therefore winning by probability of 1/2. 

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