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 June 30th, 2014, 03:17 PM #1 Newbie   Joined: Jun 2014 From: Texas Posts: 2 Thanks: 0 Factor perfect square trinomials!! Helppp 1). X^2 - 10x + 25 - y^2 2). X^2 - 18x + 81 - y^2 June 30th, 2014, 03:43 PM #2 Math Team   Joined: Dec 2006 From: Lexington, MA Posts: 3,267 Thanks: 408 Hello, Jazzy bell! There's a big hint in the title. I'll do the first one. $\quad x^2 - 10x + 25 - y^2$ Note that the first three terms form a square. So we have: $\:(x-5)^2 - y^2$ Now we have the "difference of squares". $\qquad (x-5 - y)(x-5 + y)$ Got it? Thanks from perfect_world June 30th, 2014, 04:29 PM #3 Newbie   Joined: Jun 2014 From: Texas Posts: 2 Thanks: 0 Yes I get it! Ok so would two go like this: x^2 - 18x + 81 - y^2 (x-9)^2 - 81 + 81 - y^2= (x-9)^2 -y^2 =(x-9-y)(x-9+y) Last edited by skipjack; July 1st, 2014 at 12:32 AM. June 30th, 2014, 07:22 PM #4 Math Team   Joined: Dec 2006 From: Lexington, MA Posts: 3,267 Thanks: 408 Hello, Jazzy bell! You got it! . . . Good work! July 16th, 2014, 01:18 AM   #5
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 Originally Posted by soroban Hello, Jazzy bell! There's a big hint in the title. I'll do the first one. $\quad x^2 - 10x + 25 - y^2$ Note that the first three terms form a square. So we have: $\ x-5)^2 - y^2$ Now we have the "difference of squares". $\qquad (x-5 - y)(x-5 + y)$ Got it?
Very nice answer  Tags factor, helppp, perfect, square, trinomials Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post redount2k9 Algebra 3 January 1st, 2013 07:57 PM harrypham Number Theory 8 July 19th, 2012 03:12 PM elim Number Theory 6 September 10th, 2011 11:00 PM PRO Number Theory 6 August 3rd, 2011 05:38 PM calligraphy Number Theory 4 February 10th, 2011 05:34 AM

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