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June 30th, 2014, 04:17 PM   #1
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Unhappy Factor perfect square trinomials!! Helppp

1). X^2 - 10x + 25 - y^2

2). X^2 - 18x + 81 - y^2
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June 30th, 2014, 04:43 PM   #2
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Hello, Jazzy bell!

There's a big hint in the title.
I'll do the first one.

$\quad x^2 - 10x + 25 - y^2$

Note that the first three terms form a square.

So we have: $\:(x-5)^2 - y^2$

Now we have the "difference of squares".

$\qquad (x-5 - y)(x-5 + y)$

Got it?

Thanks from perfect_world
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June 30th, 2014, 05:29 PM   #3
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Smile

Yes I get it! Ok so would two go like this: x^2 - 18x + 81 - y^2
(x-9)^2 - 81 + 81 - y^2= (x-9)^2 -y^2 =(x-9-y)(x-9+y)

Last edited by skipjack; July 1st, 2014 at 01:32 AM.
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June 30th, 2014, 08:22 PM   #4
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Hello, Jazzy bell!

You got it! . . . Good work!

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July 16th, 2014, 02:18 AM   #5
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Quote:
Originally Posted by soroban View Post
Hello, Jazzy bell!

There's a big hint in the title.
I'll do the first one.

$\quad x^2 - 10x + 25 - y^2$

Note that the first three terms form a square.

So we have: $\x-5)^2 - y^2$

Now we have the "difference of squares".

$\qquad (x-5 - y)(x-5 + y)$

Got it?

Very nice answer
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