My Math Forum Factor perfect square trinomials!! Helppp

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 June 30th, 2014, 04:17 PM #1 Newbie   Joined: Jun 2014 From: Texas Posts: 2 Thanks: 0 Factor perfect square trinomials!! Helppp 1). X^2 - 10x + 25 - y^2 2). X^2 - 18x + 81 - y^2
 June 30th, 2014, 04:43 PM #2 Math Team   Joined: Dec 2006 From: Lexington, MA Posts: 3,267 Thanks: 407 Hello, Jazzy bell! There's a big hint in the title. I'll do the first one. $\quad x^2 - 10x + 25 - y^2$ Note that the first three terms form a square. So we have: $\:(x-5)^2 - y^2$ Now we have the "difference of squares". $\qquad (x-5 - y)(x-5 + y)$ Got it? Thanks from perfect_world
 June 30th, 2014, 05:29 PM #3 Newbie   Joined: Jun 2014 From: Texas Posts: 2 Thanks: 0 Yes I get it! Ok so would two go like this: x^2 - 18x + 81 - y^2 (x-9)^2 - 81 + 81 - y^2= (x-9)^2 -y^2 =(x-9-y)(x-9+y) Last edited by skipjack; July 1st, 2014 at 01:32 AM.
 June 30th, 2014, 08:22 PM #4 Math Team   Joined: Dec 2006 From: Lexington, MA Posts: 3,267 Thanks: 407 Hello, Jazzy bell! You got it! . . . Good work!
July 16th, 2014, 02:18 AM   #5
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Quote:
 Originally Posted by soroban Hello, Jazzy bell! There's a big hint in the title. I'll do the first one. $\quad x^2 - 10x + 25 - y^2$ Note that the first three terms form a square. So we have: $\x-5)^2 - y^2$ Now we have the "difference of squares". $\qquad (x-5 - y)(x-5 + y)$ Got it?

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