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June 10th, 2019, 02:11 AM  #1 
Newbie Joined: Jun 2012 Posts: 12 Thanks: 0  How to get to this sequence?
If d1=s*(1a) and d2=s*(1a)+(1s)*(1a)*s and d3=s*(1a)+(1s)*(1a)*s+(1s)*(1a)*s how is it that the total d after n times is d=[1(1s)^n] *(1a)^n ? Last edited by skipjack; June 10th, 2019 at 04:36 AM. 
June 10th, 2019, 05:00 AM  #2 
Global Moderator Joined: Dec 2006 Posts: 20,746 Thanks: 2133 
It isn't. That doesn't work for n = 2, for example. Please check your post for typing errors. 

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