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June 10th, 2019, 02:11 AM   #1
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How to get to this sequence?

If d1=s*(1-a) and d2=s*(1-a)+(1-s)*(1-a)*s and
d3=s*(1-a)+(1-s)*(1-a)*s+(1-s)*(1-a)*s

how is it that the total d after n times is d=[1-(1-s)^n] *(1-a)^n ?

Last edited by skipjack; June 10th, 2019 at 04:36 AM.
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June 10th, 2019, 05:00 AM   #2
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It isn't. That doesn't work for n = 2, for example.

Please check your post for typing errors.
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