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 June 10th, 2019, 02:11 AM #1 Newbie   Joined: Jun 2012 Posts: 12 Thanks: 0 How to get to this sequence? If d1=s*(1-a) and d2=s*(1-a)+(1-s)*(1-a)*s and d3=s*(1-a)+(1-s)*(1-a)*s+(1-s)*(1-a)*s how is it that the total d after n times is d=[1-(1-s)^n] *(1-a)^n ? Last edited by skipjack; June 10th, 2019 at 04:36 AM.
 June 10th, 2019, 05:00 AM #2 Global Moderator   Joined: Dec 2006 Posts: 20,969 Thanks: 2219 It isn't. That doesn't work for n = 2, for example. Please check your post for typing errors. Thanks from wortel and topsquark

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