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January 28th, 2019, 02:55 PM   #1
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e^-3.5555x = 0

It says solve for x. I have no idea how to do this. It is a question on my exponents assignment. Thanks. Maybe I'm completely missing something simple. If you think it's unsolvable at this level, please say so too!

Last edited by skipjack; January 28th, 2019 at 09:21 PM.
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January 28th, 2019, 03:07 PM   #2
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Please give the EXACT and complete wording of the exercise.

There is no solution to this problem in the real numbers.
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January 28th, 2019, 03:24 PM   #3
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Quote:
Originally Posted by leahdm02 View Post
It says solve for x. I have no idea how to do this. It is a question on my exponents assignment. Thanks. Maybe I'm completely missing something simple. If you think it's unsolvable at this level, please say so too!
It's unsolvable at any level since the exponential function is never zero for real or complex exponents.
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Last edited by skipjack; January 28th, 2019 at 09:25 PM.
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January 28th, 2019, 03:36 PM   #4
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Do you mean $\displaystyle e^x =-3.5$?
$\displaystyle x=\ln(-3.5)\;$ is a complex solution.
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Last edited by skipjack; January 28th, 2019 at 09:17 PM.
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January 28th, 2019, 09:15 PM   #5
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Quote:
Originally Posted by idontknow View Post
Do you mean $\displaystyle e^x =-3.5$?
$\displaystyle x=\ln(-3.5)\;$ is a complex solution.
Oh, that's so obvious now that you pointed it out. I'm terrible at figuring out what questions actually mean. Good catch!

Last edited by skipjack; January 28th, 2019 at 09:18 PM.
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