
PreCalculus PreCalculus Math Forum 
 LinkBack  Thread Tools  Display Modes 
November 8th, 2018, 05:15 PM  #11 
Senior Member Joined: May 2016 From: USA Posts: 1,250 Thanks: 516  
November 8th, 2018, 06:06 PM  #12  
Global Moderator Joined: Dec 2006 Posts: 20,098 Thanks: 1905  Quote:
Once you have the correct inverse, namely $\phi^{1}(x) = (x + 13)/3$, applying it to the second equation gives $f(x)  3 = ((3x  4) + 13)/3 = x + 3$, so $f(x) = x + 6$.  

Tags 
embedded, functions, method, problem, shown, work 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Assorted questions, with no work shown.  LIPTON  Physics  1  June 28th, 2012 10:33 AM 
Verifying answer (with work shown)  Kimmysmiles0  Algebra  2  April 29th, 2012 09:38 PM 
Compound interest  no work shown  Arley  Algebra  1  March 22nd, 2012 08:51 PM 
Weird Embedded Cubes Problem  Recipe  Algebra  3  March 17th, 2010 07:10 PM 
Compound interest  no work shown  Arley  Calculus  0  December 31st, 1969 04:00 PM 