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November 8th, 2018, 04:15 PM  #11 
Senior Member Joined: May 2016 From: USA Posts: 1,310 Thanks: 550  
November 8th, 2018, 05:06 PM  #12  
Global Moderator Joined: Dec 2006 Posts: 20,384 Thanks: 2011  Quote:
Once you have the correct inverse, namely $\phi^{1}(x) = (x + 13)/3$, applying it to the second equation gives $f(x)  3 = ((3x  4) + 13)/3 = x + 3$, so $f(x) = x + 6$.  

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