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September 17th, 2018, 07:03 AM  #1 
Senior Member Joined: Aug 2014 From: India Posts: 331 Thanks: 1  How to solve this confusing Simple interest problem?
A sum of Rs 3,974 is lent to at SI at a rate which makes it 5 1/2 times of itself in 9 years. What will be the ratio of final amount. When the same amount is put at SI for 13 years and 17 years respectively? Ans: 15:19 
September 17th, 2018, 04:11 PM  #2  
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 13,282 Thanks: 931  Quote:
An amount of 3,974 is lent at Simple Interest at a rate which makes that amount 5 1/2 times of itself in 9 years. What will be the ratio of final amounts when the same amount earns the same rate for 13 years and 17 years? 3974 * 5.5 = 21857 (value after 9 years) (21857  3974) / 9 = 1987 (annual interest amount) 3974 + 1987 * 13 = 29805 (value after 13 years) 3974 + 1987 * 17 = 37753 (value after 17 years) Resulting ratio = 29805 / 37753 = ?  
September 18th, 2018, 12:35 AM  #3 
Global Moderator Joined: Dec 2006 Posts: 19,701 Thanks: 1804 
If the question was asking for the ratio (of each final amount) to the original amount, those ratios would be 29805/3974 and 37753/3974, which simply to 7 1/2 and 9 1/2 respectively.


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