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 September 17th, 2018, 07:03 AM #1 Senior Member   Joined: Aug 2014 From: India Posts: 470 Thanks: 1 How to solve this confusing Simple interest problem? A sum of Rs 3,974 is lent to at SI at a rate which makes it 5 1/2 times of itself in 9 years. What will be the ratio of final amount. When the same amount is put at SI for 13 years and 17 years respectively? Ans: 15:19 September 17th, 2018, 04:11 PM   #2
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Quote:
 Originally Posted by Ganesh Ujwal A sum of Rs 3,974 is lent to at SI at a rate which makes it 5 1/2 times of itself in 9 years. What will be the ratio of final amount. When the same amount is put at SI for 13 years and 17 years respectively?
Re-wording in proper English:
An amount of 3,974 is lent at Simple Interest at a rate
which makes that amount 5 1/2 times of itself in 9 years.
What will be the ratio of final amounts when the same
amount earns the same rate for 13 years and 17 years?

3974 * 5.5 = 21857 (value after 9 years)

(21857 - 3974) / 9 = 1987 (annual interest amount)

3974 + 1987 * 13 = 29805 (value after 13 years)

3974 + 1987 * 17 = 37753 (value after 17 years)

Resulting ratio = 29805 / 37753 = ? September 18th, 2018, 12:35 AM #3 Global Moderator   Joined: Dec 2006 Posts: 20,972 Thanks: 2222 If the question was asking for the ratio (of each final amount) to the original amount, those ratios would be 29805/3974 and 37753/3974, which simply to 7 1/2 and 9 1/2 respectively. Thanks from Ganesh Ujwal Tags confusing, interest, problem, simple, solve Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post grace25 Elementary Math 12 January 24th, 2013 08:46 PM shilpa Algebra 1 February 3rd, 2012 03:04 PM kieth89 Elementary Math 4 January 11th, 2012 06:05 PM Qwertyqwerty Elementary Math 2 September 20th, 2011 10:41 PM Ayeshaa Calculus 1 May 24th, 2010 03:57 AM

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