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 March 10th, 2018, 02:14 AM #1 Newbie   Joined: Mar 2018 From: US Posts: 2 Thanks: 1 How to solve What is in area P∞? Let P0 be an equilateral triangle of area 10. Each side of P0 is trisected, and the corners are snipped off, creating a new polygon (in fact, a hexagon) P1. What is the area of P1? Now repeat the process to P1 – i.e. trisect each side and snip off the corners – to obtain a new polygon P2. What is the area of P2? Now repeat this process infinitely often to create an object P∞. What is the area of P∞?
 March 22nd, 2018, 02:15 PM #2 Global Moderator   Joined: Dec 2006 Posts: 20,307 Thanks: 1976 Sorry about delay.
 March 27th, 2018, 08:53 AM #3 Math Team   Joined: Jan 2015 From: Alabama Posts: 3,261 Thanks: 896 Let A be the area of the original equilateral triangle. If you draw the lines connecting the 1/3 length segments, then you cut off 3 small triangles, each with area (1/3)^2= 1/9 of the original triangle so cut off 3/9= 1/3 of the original triangle, leaving (2/3)A. Each cut also converts each vertex into two vertices. So we now have a figure with 6 vertices of area (2/3)A. If we now cut off corners at the 1/3 length points, we are cutting off 6 triangles each with are (1/9)(2/3)A= (2/27)A so we are cutting off total area 6(2/27)A= (4/9)A, leaving (2/3- 4/9)A= (6/9- 4/9)A= (2/9)A. Continue in that way to convince yourself that, at the "n"th step, you are left with \$\left(\frac{2}{3^n}\right)A[/tex]. Taking the limit as n goes to infinity, that goes to 0.

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