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 October 22nd, 2017, 02:21 AM #1 Newbie   Joined: Oct 2017 From: canada Posts: 3 Thanks: 0 Why moving by 2 comes first then horizontal reflection? Untitled.png Why moving by 2 comes first, then horizontal reflection? Thanks. Last edited by skipjack; November 8th, 2017 at 08:21 AM.
 October 22nd, 2017, 09:43 AM #2 Senior Member     Joined: Sep 2015 From: USA Posts: 2,009 Thanks: 1042 if you moved by 2 first and then reflected you would end up with $-(x-2) = -x + 2 \neq -x - 2$
 November 8th, 2017, 04:45 AM #3 Math Team   Joined: Jan 2015 From: Alabama Posts: 3,244 Thanks: 887 "Move by 2" in which direction? -x- 2= -(x+ 2) so you can "move by 2" to the right on the number line, then "reflect" across the x-axis. For example, if x= 3, moving to the right makes it 5 and reflecting across the x-axis give -5. But you don't have to do it that way. You could, first, reflect across the x-axis so that x becomes -x, then "move by 2" to the left. If x= 3, reflecting across the x-axis give -3 and then moving to the left by 2, again -5. Last edited by skipjack; November 8th, 2017 at 08:20 AM.
November 8th, 2017, 08:28 AM   #4
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Quote:
 Originally Posted by ninjaapple Why moving by 2 . . .
Translating what by 2 in what direction?

Quote:
 Originally Posted by ninjaapple . . . then horizontal reflection?
Reflection of what in what line?

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