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October 22nd, 2017, 02:21 AM  #1 
Newbie Joined: Oct 2017 From: canada Posts: 3 Thanks: 0  Why moving by 2 comes first then horizontal reflection? Last edited by skipjack; November 8th, 2017 at 08:21 AM. 
October 22nd, 2017, 09:43 AM  #2 
Senior Member Joined: Sep 2015 From: USA Posts: 1,856 Thanks: 963 
if you moved by 2 first and then reflected you would end up with $(x2) = x + 2 \neq x  2$ 
November 8th, 2017, 04:45 AM  #3 
Math Team Joined: Jan 2015 From: Alabama Posts: 3,097 Thanks: 847 
"Move by 2" in which direction? x 2= (x+ 2) so you can "move by 2" to the right on the number line, then "reflect" across the xaxis. For example, if x= 3, moving to the right makes it 5 and reflecting across the xaxis give 5. But you don't have to do it that way. You could, first, reflect across the xaxis so that x becomes x, then "move by 2" to the left. If x= 3, reflecting across the xaxis give 3 and then moving to the left by 2, again 5.
Last edited by skipjack; November 8th, 2017 at 08:20 AM. 
November 8th, 2017, 08:28 AM  #4 
Global Moderator Joined: Dec 2006 Posts: 18,844 Thanks: 1566  

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