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October 22nd, 2017, 03:21 AM   #1
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Why moving by 2 comes first then horizontal reflection?

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Why moving by 2 comes first, then horizontal reflection?

Thanks.

Last edited by skipjack; November 8th, 2017 at 09:21 AM.
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October 22nd, 2017, 10:43 AM   #2
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if you moved by 2 first and then reflected you would end up with

$-(x-2) = -x + 2 \neq -x - 2$
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November 8th, 2017, 05:45 AM   #3
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"Move by 2" in which direction? -x- 2= -(x+ 2) so you can "move by 2" to the right on the number line, then "reflect" across the x-axis. For example, if x= 3, moving to the right makes it 5 and reflecting across the x-axis give -5. But you don't have to do it that way. You could, first, reflect across the x-axis so that x becomes -x, then "move by 2" to the left. If x= 3, reflecting across the x-axis give -3 and then moving to the left by 2, again -5.

Last edited by skipjack; November 8th, 2017 at 09:20 AM.
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November 8th, 2017, 09:28 AM   #4
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Quote:
Originally Posted by ninjaapple View Post
Why moving by 2 . . .
Translating what by 2 in what direction?

Quote:
Originally Posted by ninjaapple View Post
. . . then horizontal reflection?
Reflection of what in what line?
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