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 September 9th, 2017, 05:51 PM #1 Member   Joined: Apr 2017 From: New York Posts: 63 Thanks: 6 graphing Hi guys, How can I graph this, please teach me. question: graph (x^2+x-20) / |x-4|
 September 9th, 2017, 06:48 PM #2 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,786 Thanks: 1029 Math Focus: Elementary mathematics and beyond $$\frac{x^2+x-20}{|x-4|}\equiv\frac{(x-4)(x+5)}{|x-4|}$$ Since the denominator is zero at x = 4, we have a singularity there but it's removable, as the numerator has a factor of x - 4. Now plot x + 5 and -x - 5, using various values for x, on the same axes with a "hole" (hollow circle) at x = 4, then join the dots with a line. There are two branches, one with negative slope (-x - 5) and one with positive slope (x + 5), so be mindful of where the function "jumps" between branches (at x = 4). Don't forget to title and label your graph accordingly. Thanks from Leonardox
September 9th, 2017, 11:55 PM   #3
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Quote:
 Originally Posted by greg1313 Since the denominator is zero at x = 4, we have a singularity there . . .
I take it you mean "potential singularity", but see below.

Quote:
 Originally Posted by greg1313 but it's removable, . . .
What makes you think that? It's not.

 September 10th, 2017, 04:45 AM #4 Global Moderator     Joined: Oct 2008 From: London, Ontario, Canada - The Forest City Posts: 7,786 Thanks: 1029 Math Focus: Elementary mathematics and beyond I simply failed to give it due consideration.

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