
PreCalculus PreCalculus Math Forum 
 LinkBack  Thread Tools  Display Modes 
May 17th, 2017, 08:49 PM  #1 
Newbie Joined: May 2017 From: Surrey Posts: 1 Thanks: 0  Plz help asap need help now (function transformations)
What happens to the points (12, 6) in the functions: Y=√f(x) + 2 (f and (x) are both square rooted) y=1/3f(3(x+2))4? 
June 2nd, 2017, 05:52 AM  #2  
Math Team Joined: Jan 2015 From: Alabama Posts: 2,487 Thanks: 630  Quote:
Now, when you refer to the point (12, 6) do you mean that (12, 6) is on the graph of y= f(x) so that f(12)= 6? If so then f(x)+ 2= 4 and √(4) is not a real number. Quote:
Assuming, as above, that you mean that f(12)= 6, to evaluate f(3(x+ 2)) with only that information, must have 3(x+ 2)= 12 so that x+2= 4 and x= 2. In that case, if you intend (1/3)(f(3(x+2)) 4= that is (1/3)(6)+ 4= 2+ 4= 6. If you intend 1/(3f(3(x+2) 4 that is 1/(1+ 4= 4+ 1/18. If you intend 1/(3f(3(x+2) 4) that is 1/(18+ 4)= 1/14.  

Tags 
asap, function, plz, transformations 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Need help asap!  Zery  Algebra  6  August 1st, 2015 10:58 PM 
ASAP! Please Help With This!  Hithere  Algebra  1  November 26th, 2013 01:22 PM 
I need help ASAP  HBDB  Algebra  2  August 6th, 2008 07:14 AM 
help please ASAP  helpmewithmath  Algebra  2  June 13th, 2008 06:01 PM 
help pls !!! asap  harukasan  Advanced Statistics  2  November 28th, 2007 02:54 PM 