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March 27th, 2017, 05:35 AM  #11 
Newbie Joined: Mar 2017 From: leuven Posts: 20 Thanks: 0 
i'm going to be taking a serious look at this later this evening, going to try and understand everything by reading the comments and trying to get the logic. Sorry for the kind of late reaction, i'm really happy to get all this help! i'm having try out lessons at uni first but this evening i'm going to try to solve it using the reactions here. 
March 27th, 2017, 01:58 PM  #12 
Newbie Joined: Mar 2017 From: leuven Posts: 20 Thanks: 0 
i can safely say that i got it finally! i never viewed math in this way before. In school it has always been way more linear. Its quite a fun excercise once you know it. f(2)+2.f(12)=2 f(0)+0*f(10)=0 f(0)=0 f(1)+1*f(11)=1 f(1)+0=1 f(1)=1 f(2)+2*f(12)=2 f(2)+2*f(1)=2... f(1)+1*f(11)=1 f(1)1*f(2)=1 y z f(2)+2*f(1)=2 z y f(1)1*f(2)=1 y+2z=2 y=22z zy=1 z=1+y = y+2(y1)=2 y+2y2=2 3y =4 y=4/3 TEST: f(2)+2*f(1)=2 4/3+2f(1)=2 4/3+2*1/3=2 (1)=z=1+4/3 4/3+2/3=6/3=2 (1)=3/3+4/3 f(2)=4/3 (1)=1/3 this might be a bit chaotic to see, since the lay out didn't save, but this was all typed by me, so as to prove that i finally seem to understand it. I must say that it felt sooo satisfying once i understood it. well thats 3 days for one excercise on page 11/100 Lets hope the rest of this math course is easyer or i become smarter haha. otherwise i'l be quite far from passing my exam. Last edited by vlekje5; March 27th, 2017 at 02:01 PM. 

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base, function, guessing, meets, real, requirements 
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