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November 17th, 2016, 10:12 AM   #1
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Absolute value inequality

Solve f(x)=(|x+3|+x)/(x+2)>1

My solution:

|x+3|>2

my answer- (-∞,-5)U(-1,∞) except -2

I do not know what mistake I'm doing,because my answer is wrong, please cope with me as it is my first question.
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November 17th, 2016, 10:45 AM   #2
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Well -2 is not part of the union, so there's probably no need to mention it.
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November 17th, 2016, 10:46 AM   #3
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Also, consider what happens if $x+2 \lt 0$.

The answer you have assumes $x+2 \gt 0$, which has an impact on the answer you quoted.
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Last edited by v8archie; November 17th, 2016 at 10:49 AM.
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November 17th, 2016, 10:51 AM   #4
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Quote:
Originally Posted by 10ishq View Post
I do not know what mistake I'm doing, because my answer is wrong, . . .
Your answer was incorrect, but can you post your working, so that we can identify any mistake(s) in it?
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