November 17th, 2016, 10:12 AM  #1 
Newbie Joined: Nov 2016 From: India Posts: 1 Thanks: 0  Absolute value inequality
Solve f(x)=(x+3+x)/(x+2)>1 My solution: x+3>2 my answer (∞,5)U(1,∞) except 2 I do not know what mistake I'm doing,because my answer is wrong, please cope with me as it is my first question. 
November 17th, 2016, 10:45 AM  #2 
Math Team Joined: Dec 2013 From: Colombia Posts: 6,447 Thanks: 2120 Math Focus: Mainly analysis and algebra 
Well 2 is not part of the union, so there's probably no need to mention it.

November 17th, 2016, 10:46 AM  #3 
Math Team Joined: Dec 2013 From: Colombia Posts: 6,447 Thanks: 2120 Math Focus: Mainly analysis and algebra 
Also, consider what happens if $x+2 \lt 0$. The answer you have assumes $x+2 \gt 0$, which has an impact on the answer you quoted. Last edited by v8archie; November 17th, 2016 at 10:49 AM. 
November 17th, 2016, 10:51 AM  #4 
Global Moderator Joined: Dec 2006 Posts: 16,602 Thanks: 1200  

Tags 
absolute, absolute value, calculus, functions, inequality 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Triangle Inequality: Prove Absolute Value Inequality  StillAlive  Calculus  5  September 2nd, 2016 11:45 PM 
Absolute value inequality  Rexan  Algebra  7  June 1st, 2015 07:28 AM 
Absolute Value Inequality with Absolute Values on Both Sides  shiseonji  Algebra  2  September 24th, 2013 08:36 AM 
Absolute Inequality with LC?  Zealotor  Algebra  0  August 14th, 2010 05:17 AM 
Absolute Value Inequality  symmetry  Algebra  3  June 8th, 2007 06:26 PM 