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 November 17th, 2016, 10:12 AM #1 Newbie   Joined: Nov 2016 From: India Posts: 1 Thanks: 0 Absolute value inequality Solve f(x)=(|x+3|+x)/(x+2)>1 My solution: |x+3|>2 my answer- (-∞,-5)U(-1,∞) except -2 I do not know what mistake I'm doing,because my answer is wrong, please cope with me as it is my first question.
 November 17th, 2016, 10:45 AM #2 Math Team   Joined: Dec 2013 From: Colombia Posts: 6,346 Thanks: 2084 Math Focus: Mainly analysis and algebra Well -2 is not part of the union, so there's probably no need to mention it.
 November 17th, 2016, 10:46 AM #3 Math Team   Joined: Dec 2013 From: Colombia Posts: 6,346 Thanks: 2084 Math Focus: Mainly analysis and algebra Also, consider what happens if $x+2 \lt 0$. The answer you have assumes $x+2 \gt 0$, which has an impact on the answer you quoted. Thanks from topsquark Last edited by v8archie; November 17th, 2016 at 10:49 AM.
November 17th, 2016, 10:51 AM   #4
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Quote:
 Originally Posted by 10ishq I do not know what mistake I'm doing, because my answer is wrong, . . .
Your answer was incorrect, but can you post your working, so that we can identify any mistake(s) in it?

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