My Math Forum Derivative of logarithm

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October 29th, 2016, 12:08 PM   #1
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Derivative of logarithm

Hello,
Could you give me, how can simplified fraction?
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 October 29th, 2016, 12:16 PM #2 Math Team   Joined: Jul 2011 From: Texas Posts: 2,755 Thanks: 1405 let $k=\log_2{e}$ $\dfrac{\frac{k}{n}}{\frac{1}{2\sqrt{n}}}= \dfrac{k}{n} \cdot \dfrac{2\sqrt{n}}{1}=\dfrac{2k}{\sqrt{n}}$ Thanks from life24
October 29th, 2016, 12:51 PM   #3
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Thank you, but this derivative is correct?
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 October 29th, 2016, 12:58 PM #4 Math Team   Joined: Jul 2011 From: Texas Posts: 2,755 Thanks: 1405 Yes. Thanks from life24
October 29th, 2016, 01:02 PM   #5
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Quote:
 Originally Posted by skeeter Yes.
But i think :
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 October 29th, 2016, 01:10 PM #6 Math Team   Joined: Jul 2011 From: Texas Posts: 2,755 Thanks: 1405 $\dfrac{1}{\ln{2}} = \dfrac{\ln{e}}{\ln{2}} = \log_2{e}$ Thanks from life24
 October 29th, 2016, 01:12 PM #7 Senior Member   Joined: Feb 2014 Posts: 114 Thanks: 1 Very helpful. Thanks
October 30th, 2016, 03:31 PM   #8
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How can solve it?
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 October 30th, 2016, 03:59 PM #9 Math Team   Joined: Jul 2011 From: Texas Posts: 2,755 Thanks: 1405 In future, start a new problem with a new thread. Also, derivative problems belong in the Calculus forum. chain rule ... $\bigg[(\ln{u})^3\bigg]' = 3(\ln{u})^2 \cdot \dfrac{u'}{u}$ Thanks from topsquark and life24

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