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October 29th, 2016, 12:08 PM   #1
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Derivative of logarithm

Hello,
Could you give me, how can simplified fraction?
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October 29th, 2016, 12:16 PM   #2
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let $k=\log_2{e}$

$\dfrac{\frac{k}{n}}{\frac{1}{2\sqrt{n}}}= \dfrac{k}{n} \cdot \dfrac{2\sqrt{n}}{1}=\dfrac{2k}{\sqrt{n}}$
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October 29th, 2016, 12:51 PM   #3
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Thank you, but this derivative is correct?
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October 29th, 2016, 12:58 PM   #4
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Yes.
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October 29th, 2016, 01:02 PM   #5
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Quote:
Originally Posted by skeeter View Post
Yes.
But i think :
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October 29th, 2016, 01:10 PM   #6
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$\dfrac{1}{\ln{2}} = \dfrac{\ln{e}}{\ln{2}} = \log_2{e}$
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October 29th, 2016, 01:12 PM   #7
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Very helpful. Thanks
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October 30th, 2016, 03:31 PM   #8
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How can solve it?
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October 30th, 2016, 03:59 PM   #9
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In future, start a new problem with a new thread. Also, derivative problems belong in the Calculus forum.

chain rule ...

$\bigg[(\ln{u})^3\bigg]' = 3(\ln{u})^2 \cdot \dfrac{u'}{u}$
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