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September 16th, 2016, 04:30 AM   #1
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complex number problem

(1+i√3)^2=
Can u guys solve this one for me? the answer has to be -8
Thanks
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September 16th, 2016, 05:04 AM   #2
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That seems to be mistyped, as (1+i√3)^3 = -8.
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September 16th, 2016, 05:17 AM   #3
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we have
$1+i\sqrt{3}=2(\frac{1}{2}+i\frac{\sqrt{3}}{2})=2e ^{i\frac{\pi}{3}}$

thus

$(1+i\sqrt{3})^3=2^3e^{i\pi}=-8$
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September 16th, 2016, 05:33 AM   #4
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u are right guys im sorry thanks for making this clear
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