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June 8th, 2016, 10:18 AM  #1 
Newbie Joined: Jun 2016 From: U.Sa Posts: 1 Thanks: 0  Help with a few log equations
A few problems that I'm a little stumped on. A) e^x + 6e^x  7 =0 What I tried to do here is move the 6e^x to the right and convert to natural log. So. ln(e^x7)=ln (6e^x) or ln 6 + x on the right. Since ln e to an exponent is the exponent. After that I'm stumped. I assume I can make the left side x ln (e7) = ln 6 + x but I'm lost after that. B) log base 3 (x2) + log base 3 (2x3) = 5 log base 3 (x) I subtracted the right and made it into log base 3 (x2)(2x3)/x^5 but that's it. 
June 8th, 2016, 10:39 AM  #2 
Math Team Joined: Dec 2013 From: Colombia Posts: 7,330 Thanks: 2455 Math Focus: Mainly analysis and algebra 
A) Multiply the original equation through by $\mathrm e^{x}$ and note that $\mathrm e^{2x}=(\mathrm e^x)^2$ B) From where you are use $3^{\log_3 y} = y$ Last edited by v8archie; June 8th, 2016 at 10:41 AM. 
June 10th, 2016, 06:00 AM  #3  
Math Team Joined: Jan 2015 From: Alabama Posts: 3,240 Thanks: 885  Quote:
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