June 1st, 2016, 08:51 PM  #1 
Newbie Joined: Dec 2015 From: North America Posts: 20 Thanks: 2 Math Focus: my graphics calculator  refreshing complex numbers
Hello all! Thanks to all of you that have been so helpful... 'i' (the italicized version) is equal to root(1) if that is the case, i^9 power should still equal root(1)...? am I right? 
June 1st, 2016, 08:57 PM  #2 
Senior Member Joined: Feb 2016 From: Australia Posts: 1,797 Thanks: 633 Math Focus: Yet to find out. 
Yes. $\displaystyle i^9 = i$ 
June 1st, 2016, 08:59 PM  #3 
Math Team Joined: Nov 2014 From: Australia Posts: 689 Thanks: 244 
That's correct, yes. The powers of $i$ cycle with a period of 4. $i^{4k} = 1$, $i^{4k + 1} = i$, $i^{4k + 2} = 1$ and $i^{4k + 3} = i$. 

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