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fishgoglugglugglug June 1st, 2016 08:51 PM

refreshing complex numbers
 
Hello all! Thanks to all of you that have been so helpful...

'i' (the italicized version) is equal to root(-1)

if that is the case, i^9 power should still equal root(-1)...?

am I right?

Joppy June 1st, 2016 08:57 PM

Yes.

$\displaystyle i^9 = i$

Azzajazz June 1st, 2016 08:59 PM

That's correct, yes. The powers of $i$ cycle with a period of 4.

$i^{4k} = 1$, $i^{4k + 1} = i$, $i^{4k + 2} = -1$ and $i^{4k + 3} = -i$.


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