My Math Forum  

Go Back   My Math Forum > High School Math Forum > Pre-Calculus

Pre-Calculus Pre-Calculus Math Forum


Reply
 
LinkBack Thread Tools Display Modes
March 2nd, 2016, 01:51 PM   #1
mat
Newbie
 
Joined: Mar 2016
From: California

Posts: 1
Thanks: 0

Permutation with a Condition

I apologize if this is in the wrong section of the forum, or if this is not phrased using the proper terminology--I am not a mathematician.

Suppose there is a case, wherein a personal assistant must schedule seven appointments with five different individuals, with one individual "A" having three appointments. So, it looks like this:

AAABCDE for a total of seven appointments.

Now, let's suppose there is a condition that stipulates A's three appointments cannot be scheduled consecutively, so a combination like AABACDE cannot occur because it violates that condition.

Is there anyway for me to know the total number of possible scenarios (arrangements of ABCADAE where A does not appear consecutively) without writing out all the possible conditions one at a time until the list of possible scenarios has been exhausted?

Much thanks,

Mat

Last edited by mat; March 2nd, 2016 at 01:55 PM.
mat is offline  
 
March 2nd, 2016, 04:56 PM   #2
Global Moderator
 
Joined: May 2007

Posts: 6,807
Thanks: 717

Find (H) the number of all the possible positions A may have (1,3,5),(1,3,6), etc. There are 4! = 24 possible permutations for the other 4 appointments, so you final answer is 24H.
mathman is offline  
Reply

  My Math Forum > High School Math Forum > Pre-Calculus

Tags
condition, permutation



Thread Tools
Display Modes


Similar Threads
Thread Thread Starter Forum Replies Last Post
Condition for convergence please help jakejungle Calculus 1 January 26th, 2015 06:26 AM
ODE and intitial condition szz Calculus 4 October 24th, 2014 09:55 AM
I need help~ condition probability wxxsaber Advanced Statistics 0 April 21st, 2014 09:46 AM
The necessary condition mared Algebra 2 December 12th, 2013 04:07 PM
necessary and sucient condition on q for 3 to be a p.r. maximus101 Number Theory 0 October 23rd, 2012 01:39 PM





Copyright © 2019 My Math Forum. All rights reserved.