August 14th, 2010, 03:10 PM  #1 
Newbie Joined: Aug 2010 Posts: 2 Thanks: 0  PreCalculus
Sorry, I wasn't too sure where to put this but this seemed right. Anyway, I'm stuck on a couple of questions and any help would be appreciated. 1. How can you sketch the graph of y = x + 1 ? Translate the graph of y = x one unit _______. up, down, left, right. It's either up or right since it'll be positive, but I'm not too sure which one. 2. The graph of the equation y = x2 – 7 is symmetric with respect to which of the following? A.)the xaxis B.)the line 7x = y C.)the yaxis D.) the line y = x I tried to graph the equation on a graphing calculator, but it said error and couldn't graph it. 
August 14th, 2010, 04:43 PM  #2 
Senior Member Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 521 Math Focus: Calculus/ODEs  Re: PreCalculus
The first one will be horizontally translated one unit to the left. The 1 being added to x within the absolute value operator causes y to have the value it would for x only one unit smaller, or to the left. The second one I am assuming is y = x^2  7 and since it is the graph of y = x^2 translated 7 units down, would still have as its axis of symmetry, the y axis. 
August 14th, 2010, 04:49 PM  #3  
Newbie Joined: Aug 2010 Posts: 2 Thanks: 0  Re: PreCalculus Quote:
 
August 14th, 2010, 04:57 PM  #4 
Senior Member Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 521 Math Focus: Calculus/ODEs  Re: PreCalculus
You're welcome! 
August 14th, 2010, 05:21 PM  #5 
Math Team Joined: Apr 2010 Posts: 2,780 Thanks: 361  Re: PreCalculus
Hello Amanda, Some additional information on the first question: a = a als a >0 or a = 0 a = a als a < 0 or a=0 If you would make a graph of "a", all the negative values for a would be reflected with respect to the xaxis to get a. Because of this, the graph of a will touch the xaxis. If x would go 1 down, x+1 would have some negative values. 1 up would mean that x+1 would not "touch" the xaxis. So for now it is whether to the left, or to the right. It is useful to know where x+1=0. This is when x=1. The graph is afoot (x+1 increases whenever x gets larger, shifted to the right on a graph) it's slope is larger than 0. all values for x<1 will be reflected with respect to the xaxis, so, when x=1, the graph of x+1 "touches" the xaxis. That is a translation of the graph of y = x one unit to the left. Hoempa 

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