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January 27th, 2015, 04:42 AM   #1
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Question how to calculate the force needed?

How to solve these?
Don't mind the 50N in the last image.
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File Type: jpg 1422362372109712640022.jpg (93.2 KB, 1 views)
File Type: jpg 1422362440233-647970502.jpg (88.8 KB, 1 views)
File Type: jpg 14223626380851351437915.jpg (86.0 KB, 1 views)
File Type: jpg 14223626830761830832684.jpg (86.0 KB, 2 views)

Last edited by kaizzuu; January 27th, 2015 at 04:50 AM.
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January 28th, 2015, 02:24 PM   #2
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1st picture:
$\displaystyle F_{left}a=F_{right}b$

$\displaystyle 75kg\cdot 9.8\frac{N}{kg}\cdot 0.5m=F_{right}\cdot 2.5m$

$\displaystyle F_{right}=\frac{75\cdot 9.8\cdot 0.5}{2.5}N$
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January 28th, 2015, 02:29 PM   #3
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3rd picture: F=50N (same).

4th picture - solution is same like for 1st.

Last edited by skaa; January 28th, 2015 at 02:31 PM.
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