My Math Forum Are we living in a @ light speed spinning black hole?

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November 13th, 2014, 05:30 AM   #31
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 Originally Posted by M_B_S Thanks for your post! This logic is not disproofable: When a Black Hole spins with light speed. What is "in" the Black Hole? Answer only Energy = light with momentum! => E_u=pC the Big Bang
It's not proven either. Do you know for sure that a black hole only contains light? Do you have evidence for it? Black holes have an observational parameter "black hole mass", because celestial objects such as accretion disks can be observed orbiting a black hole. If a black hole is only made of light, which is massless, what is responsible for this observed property?

Quote:
 This is what E²=p²C²+m²C²C² is telling us.
That formula $\displaystyle E^2 = (pc)^2 + (mc^2)^2$just tells you the relationship between the energy carried by a particle travelling at the speed of light, its momentum and its mass. Nothing more.

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 You need good New papers on Black Hole Universe theory? Nikodem Poplawski's articles on arXiv Nikodem Poplawski's articles on arXiv
Now you're talking! I don't know enough about general relativity or metrics to be able to go through the paper and follow his theories, so I cannot give you an opinion on his work, but the paper is of higher quality than the first one you linked. He also has papers published in Phys Rev D, which is a reputable journal with peer review.

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 black files := matter => red files := light The onion of a Black Hole (Star) := parts different wavelenghts of light inner blue => outer red
I would take this with a huge pinch of salt because there is no evidence for black hole internal structure. Like I said before, anyone who claims that they know what is in the interior of a black hole for sure is wrong. However, there is no harm with experimenting with mathematical models and seeing where it leads.

I have a textbook on general relativity, so I should read it and follow the mathematics in it. Then I can debate this stuff in more detail.

November 13th, 2014, 05:38 AM   #32
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 Originally Posted by topsquark choosing the correct coordinates gives a metric for the non-rotating black hole: $\displaystyle d \tau ^2 = \left ( \frac{32 G^3M^3}{r T^2} \right ) Exp \left [ \frac{-r}{2GM} \right ] (dt'^2 - dr'^2 ) - r^2 d \theta ^2 - r^2 sin^2 (\theta) d \phi ^2$ The coordinate system being used here is kind of wacky, but there is no longer a singularity at r = 2GM! So the event horizon really isn't a singularity at all. That doesn't mean that we can simply ignore our usual coordinate system, which does have an apparent singularity.
"Apparent singularity" meaning that it might not go to $\infty$, but it otherwise behaves like you'd expect a black hole to act? I think that's the essence of the new Hawking 'black holes might not exist' thing (which, naturally, is overblown).

November 13th, 2014, 05:53 AM   #33
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 Originally Posted by Benit13 I have a textbook on general relativity, so I should read it and follow the mathematics in it. Then I can debate this stuff in more detail.
Good luck. I found it extremely challenging.

November 13th, 2014, 12:17 PM   #34
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 Originally Posted by CRGreathouse "Apparent singularity" meaning that it might not go to $\infty$, but it otherwise behaves like you'd expect a black hole to act? I think that's the essence of the new Hawking 'black holes might not exist' thing (which, naturally, is overblown).
Yes to all. The event horizon "singularity" in this case is due to the escape speed only. Popular Science has treated this like some kind of barrier. Mind you for the standard coordinate system that any mortal would use has such a singularity. The point of the wacky coordinate system is that there is no singularity there. (ie the metric components g(ij) are all non-zero real values.) You still can't get out of the black hole once you are inside, but the metric is actually well behaved at all values of r, except for r = 0.

-Dan

Last edited by topsquark; November 13th, 2014 at 12:25 PM.

November 13th, 2014, 12:51 PM   #35
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 Originally Posted by topsquark What is the purpose of this statement? I have not insulted you; I have merely said you are ignorant. Ignorance is not a sin, nor is it an insult as you clearly don't know as much about the topic as you think you do. A statement isn't an insult when it is accurate. You have shown very little evidence that you know the material or what it implies. I am not going to engage in an argument on the open Forum. But if you want to start a new thread where we can debate things and you can show me where I'm "stupid" I'm game. -Dan
I only wanted to say its the math => not you !

http://en.wikipedia.org/wiki/Ring_singularity

Last edited by M_B_S; November 13th, 2014 at 01:02 PM.

 December 21st, 2014, 12:22 AM #36 Senior Member   Joined: Nov 2013 From: Germany Posts: 179 Thanks: 1 Math Focus: Number Theory Stars moving with light speed ?! The Fastest Stars in the Universe May Approach Light Speed | WIRED The Fastest Stars in the Universe May Approach Light Speed BY MARCUS WOO 12.11.14 | 7:00 AM | PERMALINK After doing some calculations, Harvard University astrophysicists Avi Loeb and James Guillochon realized that yes, stars could go faster. Much faster. According to their analysis, which they describe in two papers recently posted online, stars can approach light speed. The results are theoretical, so no one will know definitively if this happens until astronomers detect such stellar speedsters—which, Loeb says, will be possible using next-generation telescopes. ******************** A star with mass could travel with light speed?! Yes it could because the star is part of our Black Hole Universe spinning with light speed (outer ring) The "Denkmodel" is a rotating carousel and the star on an inner ring is running faster then the rotating carousel (Universe) M_B_S
 January 5th, 2015, 01:44 AM #37 Senior Member   Joined: Apr 2014 From: Glasgow Posts: 2,155 Thanks: 731 Math Focus: Physics, mathematical modelling, numerical and computational solutions Anything can travel near to the speed of light if it is given enough kinetic energy Thanks from topsquark

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