October 21st, 2014, 05:14 PM  #1 
Member Joined: Oct 2014 From: NJ Posts: 46 Thanks: 2  How do I find my x bar?
I included a picture of the problem I am trying to solve. It reads: Replace the distributed loading with an equivalent resultant force, and specify its location on the beam measured from point O. W = 3 kn/m I got the resultant forces: (1/2)*3*3 = 4.5 kn (1/2)*1.5*3 = 2.25 kn 4.5 + 2.25 = 6.75 kn I know my general equation is: 6.75*xbar = torque I want to solve for xbar. xbar should equal 2.5m Last edited by shreddinglicks; October 21st, 2014 at 05:30 PM. 
October 22nd, 2014, 02:48 AM  #2 
Senior Member Joined: Apr 2014 From: Glasgow Posts: 2,166 Thanks: 738 Math Focus: Physics, mathematical modelling, numerical and computational solutions 
The formula you want is similar to centre of mass: $\displaystyle F\overline{x} = \sum_i F_i x_i$ or $\displaystyle \overline{x} = \frac{1}{F}\sum_i F_i x_i$ So you need to find the sum of the individual forces with their $\displaystyle x$ positions and then divide by the total force. Since you already have the individual forces given to you in the question, you need to evaluate the position each individual force. Can you do this? 

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