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October 2nd, 2019, 10:23 AM   #1
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Exclamation Collision

A body is thrown upward with a velocity of 30m/s after 5s it explodes in two pieces, one of pieces move downward with a velocity of 5m/s find the velocity of second piece in m/s ??
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October 2nd, 2019, 10:56 AM   #2
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apply conservation of linear momentum
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October 2nd, 2019, 11:36 AM   #3
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I don't understand the situation. If there's an "up," that means there's gravity. Should we assume standard gravity? I assume we're neglecting drag, and that 5 m/s is the instantaneous speed of the downward-moving piece immediately after the explosion, yes?

Even with these questions answered, we're missing information. To apply conservation of momentum, we need to know the mass ratio of the two pieces. If 5 % of the mass is going downward, it's going to be a lot different than if it's 95 %.
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October 2nd, 2019, 12:45 PM   #4
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Quote:
Originally Posted by Elize View Post
A body is thrown upward with a velocity of 30m/s after 5s it explodes in two pieces, one of pieces move downward with a velocity of 5m/s find the velocity of second piece in m/s ??
Why did it explode? Do we need to factor for explosives here?
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October 2nd, 2019, 12:58 PM   #5
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Downward velocity , $\displaystyle v=v_0 +gt$.
Upward velocity , $\displaystyle v=v_0 -gt$.
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October 2nd, 2019, 01:09 PM   #6
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Quote:
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Downward velocity , $\displaystyle v=v_0 +gt$.
Upward velocity , $\displaystyle v=v_0 -gt$.
suppose the explosion caused the pieces to be accelerated by non-constant transient forces!
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October 2nd, 2019, 01:12 PM   #7
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Quote:
Originally Posted by idontknow View Post
Downward velocity , $\displaystyle v=v_0 +gt$.
Upward velocity , $\displaystyle v=v_0 -gt$.
One piece will not be accelerating upward.

Gravity (and probably some amount of drag) are the only forces on the object, except during the explosion. Most explosions are fast enough to be treated as instantaneous relative to a five-second time frame, so we can model it as an instantaneous impulse.

There's still not enough information to solve the problem, however.
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October 2nd, 2019, 03:42 PM   #8
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Sometimes with incomplete problems like this you have to go ahead and make assumptions and call them out in the answer.

In this problem I'd assume that both pieces are the same size and say so.

Further, they want the instantaneous velocity immediately after the explosion.
So gravity and any other forces don't enter into it as they don't have any time
to cause an effect.

so assuming the original piece had a mass of 2m and broke into 2 pieces of 1m each

30 x 2m = -5m + vm
60=-5+v
v=65 m/s
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October 2nd, 2019, 05:28 PM   #9
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OK, I guess whether or not gravity comes into play is a matter of punctuation.

1) A body is thrown upward with a velocity of 30 m/s. After 5 s, it explodes in two pieces.

2) A body is thrown upward, with a velocity of 30 m/s after 5 s. It explodes in two pieces.
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October 2nd, 2019, 06:38 PM   #10
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Quote:
Originally Posted by DarnItJimImAnEngineer View Post
OK, I guess whether or not gravity comes into play is a matter of punctuation.

1) A body is thrown upward with a velocity of 30 m/s. After 5 s, it explodes in two pieces.

2) A body is thrown upward, with a velocity of 30 m/s after 5 s. It explodes in two pieces.
Actually I'm wrong. One does have to take into account gravity for that 5s to find out what the velocity at the time of the explosion was.

30 - 9.8 x 5 = -19 m/s

-38 = -5 + v

v = -33 m/s
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