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August 30th, 2019, 05:33 AM   #1
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Particle in motion velocity

A moving particle with velocity v doubles it's own velocity each second.
Find the acceleration a=?
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August 30th, 2019, 05:47 AM   #2
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$\displaystyle v=v_0 2^{t/(1~s)}$
$\displaystyle a = \frac{dv}{dt} = v_0 \frac{\ln~2}{1~s} 2^{t/(1~s)}=\frac{\ln~2}{1~s} v(t)$
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Last edited by skipjack; August 30th, 2019 at 06:35 AM.
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