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 July 16th, 2019, 08:02 PM #1 Senior Member   Joined: Aug 2014 From: India Posts: 476 Thanks: 1 How to solve this block physics problem? A block of mass $\displaystyle 10kg$ rests on a horizontal floor. The acceleration due to gravity is$\displaystyle 9.81m/s^{2}$. The coefficient of static friction between the floor and the block is$\displaystyle 0.2$. A horizontal force of $\displaystyle 10N$ is applied on the block as shown in the figure. The magnitude force of friction (in N) on the block: I can able to find $\displaystyle F_{s}^{max} = 98 * 0.2 = 19.6$; ($\displaystyle F_{n} = 9.8 * 10kg = 98$) After this how to proceed.
 July 17th, 2019, 05:51 AM #2 Math Team     Joined: Jul 2011 From: Texas Posts: 3,034 Thanks: 1621 $F_s \le \mu \cdot F_N = 0.2 \cdot 10g = 19.62 \, N$ since the applied force of 10 N < 19.62 N, the reaction force of static friction is 10 N.

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