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July 16th, 2019, 08:02 PM   #1
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How to solve this block physics problem?

A block of mass $\displaystyle 10kg$ rests on a horizontal floor. The acceleration due to gravity is$\displaystyle 9.81m/s^{2}$. The coefficient of static friction between the floor and the block is$\displaystyle 0.2$. A horizontal force of $\displaystyle 10N$ is applied on the block as shown in the figure. The magnitude force of friction (in N) on the block:

I can able to find $\displaystyle F_{s}^{max} = 98 * 0.2 = 19.6$; ($\displaystyle F_{n} = 9.8 * 10kg = 98$)

After this how to proceed.
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July 17th, 2019, 05:51 AM   #2
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$F_s \le \mu \cdot F_N = 0.2 \cdot 10g = 19.62 \, N$

since the applied force of 10 N < 19.62 N, the reaction force of static friction is 10 N.
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