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July 11th, 2019, 03:53 PM   #11
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You know Newton's Law, $\displaystyle \vec{F} = d(m\vec{v})/dt$, right?

With some cross-products and a little calculus, you can derive the rotational equivalent, $\displaystyle \vec{\tau} = {d(I \vec{\omega})}/{dt}$.

Basically, moments (or torques) transfer angular momentum similarly to how forces transfer linear momentum.
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July 11th, 2019, 04:07 PM   #12
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Quote:
Originally Posted by Micrm@ss View Post
What is the relation between torque and angular momentum?
Sorry, mm. I thought it was the OP asking, not a leading question.
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July 11th, 2019, 06:48 PM   #13
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torque and angular momentum; Torque required to stop angular momentum.
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July 11th, 2019, 08:46 PM   #14
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Quote:
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torque and angular momentum; Torque required to stop angular momentum.
Can you express that more mathematically? Hint: the precise form already appeared here.
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July 11th, 2019, 09:45 PM   #15
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Can you express that more mathematically? Hint: the precise form already appeared here.
$\displaystyle Torque = \large\frac{change\;in\; angular\; momentum}{change\; in\; time}$
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July 12th, 2019, 12:49 AM   #16
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Right! So what happens if Torque is zero?
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July 12th, 2019, 06:51 PM   #17
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Right! So what happens if Torque is zero?
Angular momentum is conserved.
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July 12th, 2019, 11:20 PM   #18
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So that should answer your question.
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