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June 16th, 2019, 03:08 PM   #1
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Deseleration

An aircraft touches down on one end of a runway at 80m s^-1 and decelerates at a rate of 2.5m s^-2 The run way is 1.38km long. How far from the other end of the runway will the plane come to stop?


I'm thinking $$s = \dfrac{ v^2 - u^2 }{2a}$$ So Our final velocity is going to be 0 V2=0 Our intial velocity is given 80 ms^-1 and accerlation or deceleration, in this case, is given as 2.5ms^-2. = 1280 m is this correct ? or do I need to know to take this off 1.38km?

Last edited by helpmeddddd; June 16th, 2019 at 03:48 PM.
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June 16th, 2019, 04:06 PM   #2
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distance from the end of the runway = $1380 - \dfrac{(0 \, m/s)^2 - (80 \, m/s)^2}{2(-2.5 \, m/s^2)}$
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June 16th, 2019, 04:10 PM   #3
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So basically 1380-1280=100m from the end of the runway the plane will stop.

It would acutally be 1310-1280 because I gave the wrong value so the plane will stop 30m from the end of the runway. coreect value is 1.31km

Last edited by helpmeddddd; June 16th, 2019 at 04:17 PM.
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