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May 15th, 2019, 10:08 AM   #1
Joined: May 2019
From: moscow

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3D Statics problem, box on an incline

Got a following problem: Box that weighs 300N in resting on a frictionless incline. Incline is on the Z-plane. Box is held at Place by cable AB and force F. Force F is in the direction -Z. Determine the tension in the cable AB and the force F.

Components go as follows:

$\displaystyle sum Fx =0 (3.2/6.21)AB=0$
$\displaystyle sum Fy=0 (-4.4/6.21)AB-300N=0$
$\displaystyle sum Fz=0 (-3/6.21)AB-F=0$

6.21 is the lenght of AB by my calculations and ABx is 3.2m ABy is -4.4m and ABz is -3m

Correct answer to this problem is 104N and 215N. and so far i have not gotten even close to these im not even sure if my equations of equilibrium are correct. Help desperately needed. Thanks.

Picture of problem:
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May 15th, 2019, 12:05 PM   #2
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$\vec{F} + \vec{W} + \vec{T} + \vec{F_N} = 0$

Looks like you forgot the normal force exerted on the box by the incline ...
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