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 May 12th, 2019, 04:58 PM #1 Senior Member   Joined: Mar 2019 From: TTF area Posts: 106 Thanks: 1 Calculate the mass deficit in this nuclear reaction Calculate the mass deficit in this nuclear reaction 12C+\frac{12}{6}C\rightarrow \frac{24}{12}Mg Information given: rest mass of a carbon-12 nucleus: 1.9921157x10^{-26} rest mass of a magnesium nucleus: 3.9817469x10^{-26} rest mass of a proton: 1.67353x10^{-27} rest mass of a neutron: 1.67492x10^{-27} speed of light= 3.00x10^{8} ms^{-1} note ^ is to the power of.
 May 12th, 2019, 09:07 PM #2 Senior Member   Joined: Mar 2019 From: TTF area Posts: 106 Thanks: 1 Calculate the mass deficit in this nuclear reaction $12C+\frac{12}{6}C\rightarrow \frac{24}{12}Mg$ Information given: rest mass of a carbon-12 nucleus: 1.9921157x10^{-26} rest mass of a magnesium nucleus: 3.9817469x10^{-26} rest mass of a proton: 1.67353x10^{-27} rest mass of a neutron: 1.67492x10^{-27} speed of light= 3.00x 10^{8} ms^{-1} note ^ is to the power of. Contact - Home - Forums - Cryptocurrency Forum - Top Last edited by helpmeddddd; May 12th, 2019 at 09:10 PM.
 May 13th, 2019, 11:53 AM #3 Senior Member   Joined: Mar 2019 From: TTF area Posts: 106 Thanks: 1 I've fixed my latex errors! hopefully. Calculate the mass deficit in this nuclear reaction $12{\rm C}+\frac{12}{6}{\rm C}\rightarrow \frac{24}{12}{\rm Mg}$ Information given: - rest mass of a carbon-12 nucleus: $1.9921157\times 10^{-26}\,{\rm kg}$ - rest mass of a magnesium nucleus: $3.9817469\times 10^{-26}\,{\rm kg}$ - rest mass of a proton: $1.67353\times 10^{-27}\,{\rm kg}$ - rest mass of a neutron: $1.67492\times 10^{-27}\,{\rm kg}$ - speed of light: $3.00\times 10^{8}\,{\rm m}\,{\rm s}^{-1}$
 May 13th, 2019, 08:58 PM #4 Senior Member   Joined: Mar 2019 From: TTF area Posts: 106 Thanks: 1 I'm thinking you add two C-12 and take it off mg-24 If so -12.157686-13.817469=1.659783 is this the answer or have I done something wrong?
 May 15th, 2019, 11:51 AM #5 Senior Member   Joined: Mar 2019 From: TTF area Posts: 106 Thanks: 1 1.9921157×10−2kg+1.9921157×10−26kg−3.98174 69×10−26kg=0.002484x10−26kg Is this correct ? Note in the question above they are both meant to be $12/6C$

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