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May 12th, 2019, 04:58 PM   #1
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Calculate the mass deficit in this nuclear reaction

Calculate the mass deficit in this nuclear reaction

12C+\frac{12}{6}C\rightarrow \frac{24}{12}Mg

Information given: rest mass of a carbon-12 nucleus: 1.9921157x10^{-26}

rest mass of a magnesium nucleus: 3.9817469x10^{-26}

rest mass of a proton: 1.67353x10^{-27}

rest mass of a neutron: 1.67492x10^{-27}

speed of light= 3.00x10^{8} ms^{-1}

note ^ is to the power of.
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May 12th, 2019, 09:07 PM   #2
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Calculate the mass deficit in this nuclear reaction

$12C+\frac{12}{6}C\rightarrow \frac{24}{12}Mg$

Information given: rest mass of a carbon-12 nucleus: 1.9921157x10^{-26}

rest mass of a magnesium nucleus: 3.9817469x10^{-26}

rest mass of a proton: 1.67353x10^{-27}

rest mass of a neutron: 1.67492x10^{-27}

speed of light= 3.00x 10^{8} ms^{-1}

note ^ is to the power of.




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Last edited by helpmeddddd; May 12th, 2019 at 09:10 PM.
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May 13th, 2019, 11:53 AM   #3
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I've fixed my latex errors! hopefully.


Calculate the mass deficit in this nuclear reaction

$12{\rm C}+\frac{12}{6}{\rm C}\rightarrow \frac{24}{12}{\rm Mg}$

Information given:

- rest mass of a carbon-12 nucleus: $1.9921157\times 10^{-26}\,{\rm kg}$

- rest mass of a magnesium nucleus: $3.9817469\times 10^{-26}\,{\rm kg}$

- rest mass of a proton: $1.67353\times 10^{-27}\,{\rm kg}$

- rest mass of a neutron: $1.67492\times 10^{-27}\,{\rm kg}$

- speed of light: $3.00\times 10^{8}\,{\rm m}\,{\rm s}^{-1}$
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May 13th, 2019, 08:58 PM   #4
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I'm thinking you add two C-12 and take it off mg-24

If so -12.157686-13.817469=1.659783 is this the answer or have I done something wrong?
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May 15th, 2019, 11:51 AM   #5
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1.9921157×10−2kg+1.9921157×10−26kg−3.98174 69×10−26kg=0.002484x10−26kg


Is this correct ?


Note in the question above they are both meant to be $12/6C$
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