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May 12th, 2019, 04:58 PM  #1 
Senior Member Joined: Mar 2019 From: TTF area Posts: 168 Thanks: 1  Calculate the mass deficit in this nuclear reaction
Calculate the mass deficit in this nuclear reaction 12C+\frac{12}{6}C\rightarrow \frac{24}{12}Mg Information given: rest mass of a carbon12 nucleus: 1.9921157x10^{26} rest mass of a magnesium nucleus: 3.9817469x10^{26} rest mass of a proton: 1.67353x10^{27} rest mass of a neutron: 1.67492x10^{27} speed of light= 3.00x10^{8} ms^{1} note ^ is to the power of. 
May 12th, 2019, 09:07 PM  #2 
Senior Member Joined: Mar 2019 From: TTF area Posts: 168 Thanks: 1 
Calculate the mass deficit in this nuclear reaction $12C+\frac{12}{6}C\rightarrow \frac{24}{12}Mg$ Information given: rest mass of a carbon12 nucleus: 1.9921157x10^{26} rest mass of a magnesium nucleus: 3.9817469x10^{26} rest mass of a proton: 1.67353x10^{27} rest mass of a neutron: 1.67492x10^{27} speed of light= 3.00x 10^{8} ms^{1} note ^ is to the power of. Contact  Home  Forums  Cryptocurrency Forum  Top Last edited by helpmeddddd; May 12th, 2019 at 09:10 PM. 
May 13th, 2019, 11:53 AM  #3 
Senior Member Joined: Mar 2019 From: TTF area Posts: 168 Thanks: 1 
I've fixed my latex errors! hopefully. Calculate the mass deficit in this nuclear reaction $12{\rm C}+\frac{12}{6}{\rm C}\rightarrow \frac{24}{12}{\rm Mg}$ Information given:  rest mass of a carbon12 nucleus: $1.9921157\times 10^{26}\,{\rm kg}$  rest mass of a magnesium nucleus: $3.9817469\times 10^{26}\,{\rm kg}$  rest mass of a proton: $1.67353\times 10^{27}\,{\rm kg}$  rest mass of a neutron: $1.67492\times 10^{27}\,{\rm kg}$  speed of light: $3.00\times 10^{8}\,{\rm m}\,{\rm s}^{1}$ 
May 13th, 2019, 08:58 PM  #4 
Senior Member Joined: Mar 2019 From: TTF area Posts: 168 Thanks: 1 
I'm thinking you add two C12 and take it off mg24 If so 12.15768613.817469=1.659783 is this the answer or have I done something wrong? 
May 15th, 2019, 11:51 AM  #5 
Senior Member Joined: Mar 2019 From: TTF area Posts: 168 Thanks: 1 
1.9921157×10−2kg+1.9921157×10−26kg−3.98174 69×10−26kg=0.002484x10−26kg Is this correct ? Note in the question above they are both meant to be $12/6C$ 

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