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 May 6th, 2019, 04:09 AM #1 Senior Member   Joined: Aug 2014 From: India Posts: 458 Thanks: 1 How to calculate horizontal and vertical components by trigonometry? A 75 N force is acting at an angle of 20 with the horizontal. Determine the horizontal and vertical components of this force.
May 6th, 2019, 06:26 AM   #2
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Quote:
 Originally Posted by Ganesh Ujwal A 75 N force is acting at an angle of 20 with the horizontal. Determine the horizontal and vertical components of this force.
If the force acts +20 degrees relative to the positive x-axis ...

$F_x = 75\cos(20^\circ) \, N$

$F_y = 75\sin(20^\circ) \, N$

May 6th, 2019, 06:32 AM   #3
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 Originally Posted by skeeter If the force acts +20 degrees relative to the positive x-axis ...
What do you mean +20 degrees ?

 May 6th, 2019, 06:38 AM #4 Senior Member   Joined: Oct 2013 From: New York, USA Posts: 660 Thanks: 87 I think skeeter means a line through the origin up and right so it is 20 degrees above the x-axis. -20 degrees would mean a line through the origin down and right so it is 20 degrees below the x-axis.
May 6th, 2019, 07:13 AM   #5
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 Originally Posted by EvanJ I think skeeter means a line through the origin up and right so it is 20 degrees above the x-axis. -20 degrees would mean a line through the origin down and right so it is 20 degrees below the x-axis.
Can you show it in a diagram?

 May 6th, 2019, 07:21 AM #6 Math Team     Joined: Jul 2011 From: Texas Posts: 3,002 Thanks: 1587 Have you studied any trigonometry?
May 6th, 2019, 10:07 AM   #7
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Quote:
 Originally Posted by Ganesh Ujwal . . . acting at an angle of 20 with the horizontal
What does the above wording mean, and what does it tell you about the direction of the force?

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