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May 6th, 2019, 04:09 AM   #1
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How to calculate horizontal and vertical components by trigonometry?

A 75 N force is acting at an angle of 20 with the horizontal.
Determine the horizontal and vertical components of this force.
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May 6th, 2019, 06:26 AM   #2
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A 75 N force is acting at an angle of 20 with the horizontal.
Determine the horizontal and vertical components of this force.
If the force acts +20 degrees relative to the positive x-axis ...

$F_x = 75\cos(20^\circ) \, N$

$F_y = 75\sin(20^\circ) \, N$
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May 6th, 2019, 06:32 AM   #3
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If the force acts +20 degrees relative to the positive x-axis ...
What do you mean +20 degrees ?
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May 6th, 2019, 06:38 AM   #4
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I think skeeter means a line through the origin up and right so it is 20 degrees above the x-axis. -20 degrees would mean a line through the origin down and right so it is 20 degrees below the x-axis.
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May 6th, 2019, 07:13 AM   #5
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I think skeeter means a line through the origin up and right so it is 20 degrees above the x-axis. -20 degrees would mean a line through the origin down and right so it is 20 degrees below the x-axis.
Can you show it in a diagram?
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May 6th, 2019, 07:21 AM   #6
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Have you studied any trigonometry?
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May 6th, 2019, 10:07 AM   #7
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Quote:
Originally Posted by Ganesh Ujwal View Post
. . . acting at an angle of 20 with the horizontal
What does the above wording mean, and what does it tell you about the direction of the force?
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