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April 6th, 2019, 06:47 AM   #1
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Pendulum in a lift

The simple pendulum, which is suspended from the ceiling of a lift oscillates with a period T, what is the period of simple pendulum in terms of T while lift is
A)ascending with an acceleration which equals g?
B) descending with an acceleration which equals g/2?
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April 6th, 2019, 08:23 AM   #2
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When the elevator is at rest or moving with a constant velocity,
$T=2\pi \sqrt{\dfrac{L}{g}}$

What do you think will happen to the pendulum’s period of motion in each case?
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April 6th, 2019, 08:43 AM   #3
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Quote:
Originally Posted by skeeter View Post
When the elevator is at rest or moving with a constant velocity,
$T=2\pi \sqrt{\dfrac{L}{g}}$

What do you think will happen to the pendulum’s period of motion in each case?
this is how I tried to solve it can you check it please?
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April 6th, 2019, 08:59 AM   #4
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$T_0 = 2\pi \sqrt{\dfrac{L}{g}}$

(a) $T = 2\pi \sqrt{\dfrac{L}{2g}} = \dfrac{T_0}{\sqrt{2}}$

(b) $T = 2\pi \sqrt{\dfrac{2L}{g}} = \sqrt{2} \cdot T_0$
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