February 5th, 2019, 05:05 PM  #11 
Banned Camp Joined: Mar 2015 From: New Jersey Posts: 1,720 Thanks: 124 
There is another way to put the data together to check you have the right formula and dimensions without deriving it. Put the formula together so the dimensions are correct. $\displaystyle \frac{\text{coulombs}}{\text{sec}}=(\frac{\text {electrons}}{L^{3}})( \frac{\text{coulombs}}{\text{electron}})(L^{2})( \frac{L}{\text{sec}}) $ So all you have to assume is that charge density has the same length units as area. Last edited by skipjack; February 5th, 2019 at 06:16 PM. 
February 5th, 2019, 06:27 PM  #12 
Global Moderator Joined: Dec 2006 Posts: 20,298 Thanks: 1971 
The denominator that NAC54321 used should be enclosed in parentheses.

February 6th, 2019, 06:50 AM  #13 
Banned Camp Joined: Mar 2015 From: New Jersey Posts: 1,720 Thanks: 124 
n=1.00x10^{28} electrons/mm^{3} d=.028 mm A=Pi(.014)^{2} = 6.16x10^{4} mm^{2} i=8.1 coulombs/sec e=1.60x10^{19} coulombs/electron v=drift velocity mm/sec i=neAv v=i/neA v=8.1/(1.00x10^{28})(1.60x10^{19})(6.16x10^{4}) v= (8.1/(1.6x6.16x10^{5}) v=8.22x10^{6} mm/sec 

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