Physics Physics Forum

April 8th, 2018, 12:32 PM   #1
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Help Me Kin Assignment

I need help with question 3...I have no idea how to solve it..
Attached Images 2018-04-07 (2).jpg (18.8 KB, 18 views) April 8th, 2018, 01:26 PM #2 Math Team   Joined: Jul 2011 From: Texas Posts: 3,093 Thanks: 1675 projectile motion in 2 dimensions ... (a) $\Delta y = v_0 \sin{\theta_0} \cdot t - \dfrac{1}{2}gt^2$ $\Delta y = -35 \, m$, $v_0 = 120 \, m/s$, $\theta_0 = 30^\circ$ solve the resulting quadratic for $t$ (b) using $t$ found in part (a) ... $\Delta x = v_0 \cos{\theta_0} \cdot t$ (c) $v_{fx} = v_0 \cos{\theta_0}$ ... velocity in the $x$ direction remains constant using $t$ found in part (a) ... $v_{fy} = v_0 \sin{\theta_0} - gt$ $\theta_f = \arctan\left(\dfrac{v_{fy}}{v_{fx}}\right)$ Thanks from mayak201 April 8th, 2018, 01:49 PM #3 Newbie   Joined: Apr 2018 From: Canada Posts: 9 Thanks: 0 3a) I got two answers as I used the quadratic formula, time cannot be negative so the answer I got is t=0.29s b) I got 5.36m so I rounded off to 5.4m c)-1.429 degrees = -1.43 degrees April 8th, 2018, 02:03 PM #4 Math Team   Joined: Jul 2011 From: Texas Posts: 3,093 Thanks: 1675 seems your calculator is in radian mode ... change to degrees Thanks from mayak201 April 8th, 2018, 02:28 PM #5 Newbie   Joined: Apr 2018 From: Canada Posts: 9 Thanks: 0 OOpsss...thank u 3a)12.29s=12.3s b)1278.25m=1278.3m c)-0.58 degrees = -0.6 degrees Last edited by mayak201; April 8th, 2018 at 02:30 PM. April 8th, 2018, 02:33 PM #6 Math Team   Joined: Jul 2011 From: Texas Posts: 3,093 Thanks: 1675 $0 = 35 + 60t - 4.9t^2$ $a=-4.9$, $b=60$, $c = 35$ $\dfrac{-b - \sqrt{b^2-4ac}}{2a} \approx 12.8 \,sec$ (b) should be $\approx 1330 \, m$ (c) should be $\approx -32^\circ$ Thanks from mayak201 Tags assignment, kin Thread Tools Show Printable Version Email this Page Display Modes Linear Mode Switch to Hybrid Mode Switch to Threaded Mode Similar Threads Thread Thread Starter Forum Replies Last Post illidan5 Number Theory 5 March 24th, 2016 05:31 AM LMW Algebra 1 November 20th, 2012 03:46 PM ron Calculus 1 October 8th, 2011 10:36 AM

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