My Math Forum Centripetal Force

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 October 26th, 2017, 02:40 PM #1 Newbie   Joined: Oct 2017 From: Oregon Posts: 1 Thanks: 0 Centripetal Force Equation difficulties I'm having trouble working this equation. Constants: Mass: 0.138kg Calibration Mass: .050kg Dependent: radius We ran trials on a centripetal apparatus with varying radii and timed the rotation period, then plotted T^2 and radius, found best fit line, and then slope. Slope = 16 Measured centripetal force= .050*9.8 = .490 N What I am having trouble is applying the Cent Force formula F=4(pi^2)rM/T^2 to solve for T^2. Last edited by hexrei; October 26th, 2017 at 03:19 PM.
October 26th, 2017, 05:14 PM   #2
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Quote:
 Originally Posted by hexrei What I am having trouble is applying the Cent Force formula F=4(pi^2)rM/T^2 to solve for T^2.
$\displaystyle F = \frac{4 \pi ^2rM}{T^2}$

$\displaystyle F \cdot T^2 = 4 \pi ^2 rM$

$\displaystyle T^2 = \frac{4 \pi ^2 rM}{F}$

-Dan

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