April 1st, 2017, 09:51 PM  #11  
Senior Member Joined: Feb 2016 From: Australia Posts: 1,397 Thanks: 479 Math Focus: Yet to find out.  Quote:
But even then, a symbolic interpretation is often more meaningful in these situations. You can fiddle around with various values of $m$ to see how it has an impact on the momentum of the ball. Try some large values for mass, then try some smaller ones, what do you observe.  
April 2nd, 2017, 04:35 AM  #12 
Math Team Joined: Jul 2011 From: Texas Posts: 2,655 Thanks: 1327 
A problem that asks for an estimate debatable? Don't believe so. One may use $20m$ as the magnitude of the initial momentum, $16m$ as the magnitude of the final momentum, and $\sqrt{20^2+16^2} \cdot m$ as the magnitude of the change in momentum. In other words, carry the scalar multiple of mass along with your calculations until you determine a reasonable estimate for the ball's mass ... which can be looked up or measured directly. By the way, you do know that weight is not the same thing as mass, correct? 
April 2nd, 2017, 03:33 PM  #13 
Member Joined: Mar 2017 From: Tasmania Posts: 36 Thanks: 2 
Yes I know that mass differs from weight. Weight is Fw = m*g where g is 9.81

April 25th, 2017, 08:13 AM  #14 
Newbie Joined: Apr 2017 From: durban Posts: 10 Thanks: 0 Math Focus: Algebra 
No you can't assume the weight


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