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March 10th, 2017, 04:37 PM   #1
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Is this correct?

So here is the question and my attempt. I won't know if I'm right until it's turned in and unfortunately the helpful peers I know are all gone around the country so I need the better next thing.

Am I right?



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March 10th, 2017, 05:01 PM   #2
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try again, leaving $\omega_0$ in RPM ... $\omega_f$ will be in RPM.

$I_0 \omega_0 = I_f \omega_f$

$(200)(10) = (200 + 25 \cdot 2^2)(\omega_f)$
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March 10th, 2017, 05:22 PM   #3
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Originally Posted by The_Ys_Guy View Post
Am I right?
It won't spin faster after the child hops on.
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March 11th, 2017, 10:40 AM   #4
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first time in my life i woke up and did a math problem........


Should I leave it in rev/min?
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March 11th, 2017, 10:44 AM   #5
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first time in my life i woke up and did a math problem........
Did you dream you were on a merry-go-round?
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March 11th, 2017, 11:20 AM   #6
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You didn't round to two decimal places correctly, so my advice is to put away the friggin' calculator and provide an exact solution ...

$\omega_f = \dfrac{20}{3}$ RPM or $\dfrac{2\pi}{9}$ rad/sec

you should know the rules for turn-in ... we don't.

which one is acceptable?
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March 11th, 2017, 01:08 PM   #7
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I didn't round at all but I see your point......

I don't know, we did examples that left it in RPM and a few that converted it to Rad/sec. I'll just do both.
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