March 10th, 2017, 04:37 PM  #1 
Member Joined: Feb 2014 Posts: 91 Thanks: 1  Is this correct?
So here is the question and my attempt. I won't know if I'm right until it's turned in and unfortunately the helpful peers I know are all gone around the country so I need the better next thing. Am I right? 
March 10th, 2017, 05:01 PM  #2 
Math Team Joined: Jul 2011 From: Texas Posts: 2,549 Thanks: 1260 
try again, leaving $\omega_0$ in RPM ... $\omega_f$ will be in RPM. $I_0 \omega_0 = I_f \omega_f$ $(200)(10) = (200 + 25 \cdot 2^2)(\omega_f)$ 
March 10th, 2017, 05:22 PM  #3 
Global Moderator Joined: Dec 2006 Posts: 17,196 Thanks: 1291  
March 11th, 2017, 10:40 AM  #4 
Member Joined: Feb 2014 Posts: 91 Thanks: 1 
first time in my life i woke up and did a math problem........ Should I leave it in rev/min? 
March 11th, 2017, 10:44 AM  #5 
Math Team Joined: Oct 2011 From: Ottawa Ontario, Canada Posts: 9,437 Thanks: 640  
March 11th, 2017, 11:20 AM  #6 
Math Team Joined: Jul 2011 From: Texas Posts: 2,549 Thanks: 1260 
You didn't round to two decimal places correctly, so my advice is to put away the friggin' calculator and provide an exact solution ... $\omega_f = \dfrac{20}{3}$ RPM or $\dfrac{2\pi}{9}$ rad/sec you should know the rules for turnin ... we don't. which one is acceptable? 
March 11th, 2017, 01:08 PM  #7 
Member Joined: Feb 2014 Posts: 91 Thanks: 1 
I didn't round at all but I see your point...... I don't know, we did examples that left it in RPM and a few that converted it to Rad/sec. I'll just do both. 

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