January 8th, 2017, 01:31 PM  #11 
Newbie Joined: Jan 2017 From: brussels Posts: 28 Thanks: 0 
i am also struggling with a very similar topic, i am trying to calculate the radius of gyration however for the experimental value it says to use the outside radius of the disc but for the experimental calculations it says use the roller radius, why would that be? and also how do i calculate the radius of gyration? i have transposed a formula to get k = √(2ghr)r^2/(v^2) r^2 but how do i use this to find what i need? 
January 9th, 2017, 01:13 PM  #12 
Senior Member Joined: Feb 2016 From: Australia Posts: 1,579 Thanks: 541 Math Focus: Yet to find out. 
I would have thought using $I = k^2 A$ would be more straight forward. Rearranging would give, $\displaystyle k = \sqrt{\dfrac{I}{A}}$ Substituting moment of inertia of a solid disk (about x,y plane), $\displaystyle k = \sqrt{\dfrac{m r^2}{4A}}$ EDIT: Experimental value? Experimental calculations? I can only guess that maybe you are required to find $k$ theoretically, then compare this result with experimental values. Or, it is all to be done theoretically, and you are to observe the differences that appear when changing point that you are measuring radius from. Last edited by Joppy; January 9th, 2017 at 01:17 PM. 
January 10th, 2017, 02:47 PM  #13 
Newbie Joined: Jan 2017 From: brussels Posts: 28 Thanks: 0 
Yes we must calculate both a theoretical value and the experimental value


Tags 
physics 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Physics IB  alex77  Physics  2  August 15th, 2016 01:27 AM 
Discrepancies in particles physics versus quantum physics  GreenBeast  Physics  16  April 8th, 2016 06:16 AM 
physics  maapony  Algebra  1  September 1st, 2011 02:34 PM 
physics help  shawdub  Physics  1  October 29th, 2010 05:11 PM 
Physics  johnny  Physics  11  October 30th, 2007 05:19 AM 