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December 6th, 2016, 08:53 AM   #1
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Torque required for synchronising generators

I'm trying to work out the answer to the following problem:

Two, four-pole (p=2), 50 Hz synchronous generators are paralleled. Their phase displacement is 2 degrees mechanical. The synchronous reactance, $\displaystyle X$, of each machine is 10 Ohms/phase and the common busbar voltage is 6.6 kV. Calculate the synchronizing torque (answer = 968 Nm).

The equation in the example problem for calculating this is:

$\displaystyle \tau_{synch} = \frac{P_{synch}}{2\pi \frac{f}{p}}$

where

$\displaystyle P_{synch} = \frac{3}{2} \frac{E^2}{X} \times \delta'_{el}$

I have no idea where this formula has come from. In the textbook the power of a turbo-generator is given as

$\displaystyle P = \frac{EV}{X} \sin \delta$

where $\displaystyle V = E/\sqrt{3}$. However, this gives a different result. Does anyone know how the first formula is derived?
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December 21st, 2016, 09:41 PM   #2
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Hi, I am not expert in this but I have fond some information about torque. I hope this will help you. What is Synchronizing Power and Torque Coefficient? - Circuit Globe

If You need direct conversion you can go for online converter tools, like AshBox, etc..
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