
Physics Physics Forum 
 LinkBack  Thread Tools  Display Modes 
December 6th, 2016, 07:53 AM  #1 
Senior Member Joined: Apr 2014 From: Glasgow Posts: 2,099 Thanks: 703 Math Focus: Physics, mathematical modelling, numerical and computational solutions  Torque required for synchronising generators
I'm trying to work out the answer to the following problem: Two, fourpole (p=2), 50 Hz synchronous generators are paralleled. Their phase displacement is 2 degrees mechanical. The synchronous reactance, $\displaystyle X$, of each machine is 10 Ohms/phase and the common busbar voltage is 6.6 kV. Calculate the synchronizing torque (answer = 968 Nm). The equation in the example problem for calculating this is: $\displaystyle \tau_{synch} = \frac{P_{synch}}{2\pi \frac{f}{p}}$ where $\displaystyle P_{synch} = \frac{3}{2} \frac{E^2}{X} \times \delta'_{el}$ I have no idea where this formula has come from. In the textbook the power of a turbogenerator is given as $\displaystyle P = \frac{EV}{X} \sin \delta$ where $\displaystyle V = E/\sqrt{3}$. However, this gives a different result. Does anyone know how the first formula is derived? 
December 21st, 2016, 08:41 PM  #2 
Newbie Joined: Dec 2016 From: United Kingdom Posts: 14 Thanks: 1 
Hi, I am not expert in this but I have fond some information about torque. I hope this will help you. What is Synchronizing Power and Torque Coefficient?  Circuit Globe If You need direct conversion you can go for online converter tools, like AshBox, etc.. 

Tags 
generators, required, synchronising, torque 
Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
Finding generators for U(Z/nZ)  numberguru1  Number Theory  7  April 8th, 2016 12:36 PM 
Difference between AC and DC generators?  rsoy  Physics  4  February 13th, 2012 06:41 PM 
Generators  sarah77  Abstract Algebra  2  April 26th, 2011 08:21 AM 
Help with finding generators  Elladeas  Abstract Algebra  3  March 8th, 2011 02:32 PM 
Order of Generators  Ciqo  Abstract Algebra  3  March 2nd, 2008 09:28 AM 