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June 30th, 2012, 11:51 AM  #1 
Senior Member Joined: Oct 2009 Posts: 895 Thanks: 1  A shaft is uniformly accelerated from 10rev/s to 18 rev/s in
A shaft is uniformly accelerated from 10rev/s to 18 rev/s in 4 sec . The shaft continues to accelerate at this rate for the next 8 sec . Thereafter the shaft rotates with a uniform angular speed . Find the total time to complete 400 rev . In fact we solved this question , but I face some confused .. I want just complete my answer ... the displacement and number of revolution at t = 12 Q = w0t + 1/2at^2 Q = 1658 rad Re = 264 rev velocity w at t = 12 w = w0 + at w= (20Pi )+(4pi)(12) w = 213.62 rad/s so t when reach 400 rev at Q = (400 X 2Pi ) = 2513 = t = (Q/w) = (2513/ 213.62) = 11 (why not come 4 ) a 
June 30th, 2012, 11:54 AM  #2 
Senior Member Joined: Oct 2009 Posts: 895 Thanks: 1  Re: A shaft is uniformly accelerated from 10rev/s to 18 rev/
sorry now I know my mistake so Q must (Q2 Q 1 ) t= 4 

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10rev or s, accelerated, rev or s, shaft, uniformly 
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