My Math Forum A shaft is uniformly accelerated from 10rev/s to 18 rev/s in

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 June 30th, 2012, 11:51 AM #1 Senior Member   Joined: Oct 2009 Posts: 895 Thanks: 1 A shaft is uniformly accelerated from 10rev/s to 18 rev/s in A shaft is uniformly accelerated from 10rev/s to 18 rev/s in 4 sec . The shaft continues to accelerate at this rate for the next 8 sec . Thereafter the shaft rotates with a uniform angular speed . Find the total time to complete 400 rev . In fact we solved this question , but I face some confused .. I want just complete my answer ... the displacement and number of revolution at t = 12 Q = w0t + 1/2at^2 Q = 1658 rad Re = 264 rev velocity w at t = 12 w = w0 + at w= (20Pi )+(4pi)(12) w = 213.62 rad/s so t when reach 400 rev at Q = (400 X 2Pi ) = 2513 = t = (Q/w) = (2513/ 213.62) = 11 (why not come 4 ) a
 June 30th, 2012, 11:54 AM #2 Senior Member   Joined: Oct 2009 Posts: 895 Thanks: 1 Re: A shaft is uniformly accelerated from 10rev/s to 18 rev/ sorry now I know my mistake so Q must (Q2 -Q 1 ) t= 4

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