
Physics Physics Forum 
 LinkBack  Thread Tools  Display Modes 
June 28th, 2012, 02:38 AM  #1 
Senior Member Joined: Oct 2009 Posts: 895 Thanks: 1  A solid steel shaft is subjected to a torque of 45 KN/m.
A solid steel shaft is subjected to a torque of 45 KN/m. If the angle of twist is 0.5 degree per meter length of the shaft and the shear stress is not exceed 90 MN/m^2 (I) find the suitable diameter of the shaft . Take C = 80 GN/m^2 (II) Maximum shear strain we can solve the question by torsion equation T/Ip = e/R = CQ/l T maximum twisting torque in Nm Ip polar moment of inertia = pid^4/32 in m^4 e shear stress in N/m^2 R radius of the shaft Q the angle of the shaft in rad l length if the shaft in m [color=#FF0000]my question know why in solving fined two diameter ? [/color] 
June 28th, 2012, 10:29 AM  #2 
Senior Member Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,211 Thanks: 521 Math Focus: Calculus/ODEs  Re: A solid steel shaft is subjected to a torque of 45 KN/m.
Do you mean why do you need to find the value of twice the radius? What is the relationship between the radius and the diameter of a circle? 
June 29th, 2012, 07:45 AM  #3 
Senior Member Joined: Oct 2009 Posts: 895 Thanks: 1  Re: A solid steel shaft is subjected to a torque of 45 KN/m.
yes why ? and here I have the solution the fist answer is Diameter on the basic of twist = 0.16 m and then diameter on the basis of shear stress : D = 0.1365 m Now my question why in answer give us two diameter ? and which one is correct ? 
June 29th, 2012, 08:44 AM  #4 
Senior Member Joined: Oct 2009 Posts: 895 Thanks: 1  Re: A solid steel shaft is subjected to a torque of 45 KN/m.
and my other question why in question written the unit of torque kN/m not KNm

June 29th, 2012, 09:28 AM  #5 
Senior Member Joined: Oct 2009 Posts: 895 Thanks: 1  Re: A solid steel shaft is subjected to a torque of 45 KN/m.
see here the solution may will help http://store2.up00.com/June12/yq190516.jpg http://store2.up00.com/June12/zj390516.jpg http://store2.up00.com/June12/dUP90516.jpg http://store2.up00.com/June12/K5m90516.jpg My questions! 1  Why in the solution there is two diameter 2  I second diameter how they got the answer 0.13 m when I do the calculation I got 0.14 not 0.13 m 3  In last from where he got the formula of maximum shear strain = RQ/l ? 

Tags 
kn or m, shaft, solid, steel, subjected, torque 
Search tags for this page 
0,45kN in N,a solid shaft subjected to torque of 45 KNM ........solution,a hollow circular shaft is required to transmit a torque of 6000Nm and is 4m long. If the maximum permissible angle twist is 2 degrees over the whole length, determine the diameter required when in the ratio of 2:1,a solid steel shaft 45 knm
Click on a term to search for related topics.

Thread Tools  
Display Modes  

Similar Threads  
Thread  Thread Starter  Forum  Replies  Last Post 
A steel plate 2 cm thick is maintained at a temperatur  rsoy  Physics  0  November 13th, 2013 11:29 PM 
A shaft is uniformly accelerated from 10rev/s to 18 rev/s in  rsoy  Physics  1  June 30th, 2012 11:54 AM 
A shaft is uniformly accelerated from 10rev/s to 18 rev/s in  rsoy  Physics  6  May 26th, 2012 06:02 PM 
Torque  benmuskler  Physics  1  March 31st, 2012 08:13 AM 
A question of Torque Measurement  FeebleBrain  Applied Math  1  August 9th, 2011 04:58 AM 