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 May 18th, 2012, 01:02 AM #1 Senior Member   Joined: Oct 2009 Posts: 895 Thanks: 1 A body is released from a great fall freely towards earth an Hi all Can explain to me more about that this question because I don't understand fully A body is released from a great fall freely towards earth another body is released from the same height exactly one second later . Find the separation between the bodies after two second of the release of the second body ? [color=#008040]As I understand It wants distance? But what is other givens ? g = 9.81 t= 2s u = zero How I can find the distance if the time of other body not given ?[/color]
 May 18th, 2012, 01:15 AM #2 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,209 Thanks: 517 Math Focus: Calculus/ODEs Re: A body is released from a great fall freely towards eart If we set time t = 0 to be at the time of the release of the second body, then the distance traveled by the first body at time t is: $d_1=\frac{1}{2}g(t+1)^2$ and the distance traveled by the second body is: $d_2=\frac{1}{2}gt^2$ and the separation between the bodies at time t is then: $d_1-d_2=\frac{1}{2}g(t+1)^2-\frac{1}{2}gt^2=\frac{1}{2}g$$(t+1)^2-t^2$$=\frac{1}{2}g$$2t+1$$$
 May 18th, 2012, 01:20 AM #3 Senior Member   Joined: Oct 2009 Posts: 895 Thanks: 1 Re: A body is released from a great fall freely towards eart Good I got H = 24.52 m
 May 18th, 2012, 09:14 AM #4 Senior Member     Joined: Jul 2010 From: St. Augustine, FL., U.S.A.'s oldest city Posts: 12,209 Thanks: 517 Math Focus: Calculus/ODEs Re: A body is released from a great fall freely towards eart If you are going to round to two decimal places, you should write h = 24.525 m ? 24.53 m.

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# a body is released from a great height and falls freely towards the earth exactly one second later another body is released what is the distance between the two bodies

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